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otez555 [7]
3 years ago
8

Round 199.532 to the nearest tenth

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0

Answer:

199.5

Step-by-step explanation:

3 is not greater than 5

ivolga24 [154]3 years ago
3 0

Answer:

199.5

Step-by-step explanation:

The tenth place is the first number to the right of the decimal, in this case, it is 5. In order to know whether or not to raise it to 6 or keep it as 5, we have to look at the hundredth's value. If the number is 5 or higher, we change 5 to 6. If the number is 4 or lower, we keep the 5. In this case, the number is 3, which is 4 or lower. We keep the 5 as it is and get rid off all the numbers behind it. Resulting in:

199.5

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20 points!<br> I need help with these!
defon

1. 113.64

(work) 947x.12

2. 130.5

(work) 435x.30 = 130.5

5 0
3 years ago
Ignore the answer I put please help and I’ll give brainliest
Leokris [45]

Answer:

B.

Step-by-step explanation:

3/12 reduces to 1/4.

1/2 alone is greater than 1/4, so when 2/10 is added to 1/2, it is certainly greater than 3/12.

Answer: B.

5 0
3 years ago
Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

5 0
3 years ago
Will give Brainliest and Five Stars to the correct answer
nadezda [96]
The correct answer is y = 1/8x^2
5 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
Read 2 more answers
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