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Stella [2.4K]
2 years ago
8

Is this equation balanced: AgNO3 + 2 KCl -->AgCl + KNO3 Yes No

Chemistry
1 answer:
frutty [35]2 years ago
5 0

Answer:

No

Explanation:

AgNO₃ + KCl --> AgCl + KNO₃

This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.

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3. What is the mass of 5 moles of Hydrogen sulfate?I
solong [7]

Answer:

490

98 for 1 mole, Hence for 5 moles 5 X 98 =490.

Explanation:

Brainliest please?

3 0
3 years ago
Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar covalent based solely on each element's positi
Amanda [17]
<span>you have to find the differences of electronegativity for the atoms joined by the bond. if their diff is <0.4,
then it's non-polar if it's between 0.4 to 1.7
then it's polar 1.7 and up it's ionic Electronegativity values can be found on most periodic tables.</span>
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3 years ago
What is a nonpolar bond?
serious [3.7K]
A bond between 2 nonmetal atoms that have the same electronegativity and therefore have equal sharing of the bonding electron pairExample: In H-H each H atom has an electronegativity value of 2.1, therefore the covalent bond between them is considered nonpolar. Nonpolar covalent bonds, with equal sharing of the bond electrons, arise when the electronegativities of the two atoms are equal.

 

8 0
3 years ago
Read 2 more answers
What is the mass of alliminum?
Gennadij [26K]

Answer:

26.981539 u

Atomic number: 13

Symbol: Al

Electron configuration: [Ne] 3s²3p¹

5 0
3 years ago
Read 2 more answers
A 35.0 ml sample of 0.225 m hbr was titrated with 42.3 ml of koh. What is the concentration of the koh?
Lemur [1.5K]

Answer:

The concentration of KOH is 0.186 M

Explanation:

First things first, we need too write out the balanced equation between HBr and KOH.

This is given as;

KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)

From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.

We use the acid base formular in calculating unknown concentrations. This is given as;

\frac{CaVa}{CbVb}  = \frac{na}{nb}

where;

Ca = Concentration of acid

Va = Volume of acid

Cb = Concentration of base

Vb = Volume of base

na = Number of moles of acid

nb = Number of moles of base

KOH is the base and HBr is acid.

Hence;

Ca = 0.225

Va = 35

Cb = ?

Vb = 42.3

na = 1

nb = 1

Making Cb subject of formular we have;

Cb = \frac{CaVaNb}{VbNa}

Cb = (0.225 * 35 * 1) / (42.3 * 1)

Cb = 0.186 M

5 0
3 years ago
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