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3 years ago

Please make sure you are correct thank you!!

Chemistry

2 answers:

blagie [28]3 years ago

6 0

Answer:

Explanation:

Steam is a gas formed when liquid is heated.

Nadya [2.5K]3 years ago

4 0

It’s F bc when it is boiling the particles flow up and gas particles go up into the air

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A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro

Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of $OH^{-}$ and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

$NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)$

So, $OH^{-}$ is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of $OH^{-}$ increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of $OH^{-}$ and keep same equilibrium constant.

Therefore excess amount of $OH^{-}$ combines with $NH_{4}^{+}$ to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

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3 years ago

The elaboration likelihood model emphasizes the use of __________ persuasion and __________ persuasion methods. A. direct . . .

Angelina_Jolie [31]

Answer:

It's C, direct and peripheral.

Explanation:

Just took the test

6 0

3 years ago

Read 2 more answers

A NaOH (aq) stock solution was created by dissolving 3.88 g NaOH in water to create a 100.00 mL solution. What is the concentrat

Ierofanga [76]

Answer:

I have don 3 so far

Explanation:

Brainlyis the best

8 0

3 years ago

Help pls I will mark brainlest

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Resources found in lithosphere: gold and iron etc

Resources found in atmosphere: Water vapor, gases etc.

4 0

3 years ago

Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st

Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have reaction called halohydrin formation. This is a markovnikov reaction with anti configuration. Therefore the halogen in this case "Br" and the "OH" must have different configurations. Additionally, in this molecule both carbons have the same substitution, so the "OH" can go in any carbon.

Finally, in the product we will have chiral carbons, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0

3 years ago