7. A student has a 25 g sample of gas in a container at STP and adds another 7
1 answer:
Answer:
New temperature t2 = [1.28T− 273.15]° C
Explanation:
Given:
Volume v1 = 25 gram
New volume v2 = 25 + 7 = 32 gram
Constant pressure = p
Temperature t1 = T
Find:
New temperature t2
Computation:
Pv1/t1 = Pv2/t2
25 / T = 32 / t2
t2 = 1.28T
New temperature t2 = [1.28T− 273.15]° C
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