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Rudik [331]
3 years ago
9

Can someone help w/ this math problem plzz

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

its C

Step-by-step explanation:

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I'm very confused on how to solve this problem, can anyone please help? Thanks!
Pepsi [2]

Answer:

.

Step-by-step explanation:

DC = 16 and

DB = 30 so

CB = 14

DB = 30 and

EB = 49 so

EB = 19

5 0
3 years ago
In two years what percent of his age will Benny’s mom be at that time since Benny is 12 and his mom is 48
Ksju [112]

Answer:

His mom’s age will be 1/% of Benny’s age at that time.

Step-by-step explanation:

14>>100%

1>>(100/14)%

50>>50(100/14)%

50>>25(100/7)%

50>>(2500/7)%

50>>357 1/7%

so in two years Benny will be 14 and his mom will be 50.

7 0
4 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
What is the total of all 3 tickets below. use the menu to solve
alex41 [277]

Answer:

$103.14

Step-by-step explanation:

The calculation of slips are amounted to a total of $103.14

5 0
2 years ago
Find the value of x.
Mariana [72]

Answer:

Step-by-step explanation:

sin^-1(7/16)= 25.9 degrees

7 0
3 years ago
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