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Semmy [17]
2 years ago
7

A student described two properties of a substance as shown.

Chemistry
1 answer:
AnnZ [28]2 years ago
3 0

Answer:

X is a chemical property and Y is a physical property.

Explanation:

i did it.

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Leni [432]
The answer is: Graphite
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3 years ago
Which action would most likely create a light waye?
ladessa [460]
The answer that h are looking for is c
8 0
2 years ago
Read 2 more answers
What would be the oxidation and reduction half reactions for this equation?
Sedbober [7]

Answer:

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

Explanation:

The redox reaction is: MgCl₂(aq) + Fe(s) → FeCl₂(aq) + Mg(s)

We need to know that elements in ground state have 0 as the oxidation state.

Iron in the reactants, and Mg in the products

In the magnessium chloride, the Mg acts with+2, so the oxidation state has decreased → REDUCTION

In the iron(II) chloride, the Fe acts with +2, so the oxidation statehas increased → OXIDATION

The half reactions are:

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

5 0
3 years ago
5. Consider the following experiment: A block of iron with an initial mass of 50 g is placed in a sealed container of pure oxyge
Vera_Pavlovna [14]

The observation in the illustration remains in accordance with the law of conservation of mass assuming that moisture is present in the container.

<h3>What is the law of conservation of mass?</h3>

The law state that mass can neither be created nor destroyed. However, mass can be converted from one form to another.

In this case, the ion was placed in a container of pure oxygen. Assuming that moisture is present, iron reacts with oxygen to form rust according to the following equation:

4Fe + 3O_2 + 6H_2O --- > 4Fe(OH)_3

The rust formed will weigh more than the initial weight of the iron.

Without the presence of moisture, one can effectively conclude that the observation violates the law of conservation of mass.

More on the law of conservation of mass can be found here: brainly.com/question/13383562

#SPJ1

8 0
2 years ago
En un balneario necesitan calentarse 1 millón de litros de agua anuales, subiendo la temperatura desde 15 ºC a 50 ºC y para ello
MAXImum [283]

Answer:

a) m_{CH_4}=2630kg

b) 1657 €

Explanation:

Hola,

a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:

Q_{H_2O}=m_{H_2O}Cp(T_2-T_1)=1x10^6LH_2O*\frac{1kgH_2O}{1LH_2O}*4.18\frac{kJ}{kg\°C}(50-15) \°C\\Q_{H_2O}=146.3x10^6kJ

Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:

Q_{H_2O}=-Q_{CH_4}=-146.3x10^5kJ=m_{CH_4}\Delta _cH_{CH_4}

m_{CH_4}= \frac{Q_{CH_4}}{\Delta _cH_{CH_4}} =\frac{-146.3x10^5kJ}{-890kJ/molCH_4} *\frac{16gCH_4}{1molCH_4} \\\\m_{CH_4}=2630112.36g=2630kg

b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:

n_{CH_4}=\frac{PV}{RT}=\frac{1atm*1000L}{0.082\frac{atm*L}{mol*K}*273K} =44.67mol

Con ello, los kilogramos de metano que cuestan 0,45 €:

44.67molCH_4*\frac{16gCH_4}{1molCH_4}*\frac{1kg}{1000g} =0.715kgCH_4

Luego, aplicamos la regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

3 0
3 years ago
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