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Elden [556K]
3 years ago
7

What is the molar mass of Ca(OH)2

Chemistry
2 answers:
ikadub [295]3 years ago
8 0

Answer:

74 gmol-1

Explanation:

Molar masses

Ca= 40

O = 16

H = 1

Molar mass of Ca(OH)2 = 40+16*2+1*2

= 40+32+2

=74

gavmur [86]3 years ago
4 0

Answer:

The molar mass of Ca(OH)2 is 74.092 g/mol

Explanation:

First your going to find the atomic mass of each element on the periodic table.

Ca(Calcium) = 40.078

O(Oxygen) = 15.999

H(Hydrogen) = 1.008

Then we can create the equation:

40.078 + (15.999 + 1.008) × 2

40.078 + (17.007) × 2

40.078 + 34.014

= 74.092 g/mol

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ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

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3 years ago
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Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
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Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

Explanation :

The given main chemical reaction is:

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The intermediate reactions are:

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(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

Thus, the equilibrium constant for this reaction will be:

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K=\frac{(K_b)^2}{K_a}

Thus, the equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

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Answer:

No.

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