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3 years ago

Enter ionic and net equations: feso4(aq)+ na3po4(aq) arrow fe3(po4)2(s)+na2so4(aq)

Chemistry

1 answer:

stepan [7]3 years ago

6 0

Answer:

ionic equation : 3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

net ionic equation: 3Fe(2+)(aq) + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

Explanation:

The balanced equation is

3FeSO4(aq)+ 2Na3PO4(aq) → Fe3(PO4)2(s)+ 3Na2SO4(aq)

Ionic equations: Start with a balanced molecular equation. Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions . Indicate the correct formula and charge of each ion. Indicate the correct number of each ion . Write (aq) after each ion .Bring down all compounds with (s), (l), or (g) unchanged. The coefficents are given by the number of moles in the original equation

3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

Net ionic equations: Write the balanced molecular equation. Write the balanced complete ionic equation. Cross out the spectator ions, it means the repeated ions that are present. Write the "leftovers" as the net ionic equation.

3Fe(2+)(aq) + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

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3 years ago

Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

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Answer: The nuclide symbol of X is $^{231}_{90}\textrm{Th}$

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

$_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}$

For the given equation :

$^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}$

As the atomic number and mass number must be equal on both sides of the nuclear equation:

$^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}$

Thus the nuclide symbol of X is $^{231}_{90}\textrm{Th}$

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3 years ago

a. Compare the motion of the particles as a solid, liquid, and gas. b. What happens to the intermolecular bonds during phase cha

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3 years ago

………… is the Energy stored in chemical bonds.

Katyanochek1 [597]

Answer:Energy, potential energy, is stored in the covalent bonds holding atoms together in the form of molecules. This is often called chemical energy. ..

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3 years ago

Read 2 more answers

Each of the following reactions is incomplete. Match each of the following particles with the correct reaction in order to compl

kiruha [24]

Answer:

1. Option A. Beta decay minus 0 -1e

2. Option B. Alpha 4 2He

3. Option A. Beta decay minus 0 -1e

Explanation:

1. 66 29Cu is undergoing beta decay minus since it produces a daughter nuclei having the same mass number and the atomic number increased by 1 i.e 66 30Zn

2. 238 92U is undergoing alpha decay since the daughter nuclei produced has a decrease of 4 in the mass number and a decrease of 2 in the atomic number ie 234 90Th

3. 14 6C is undergoing beta decay minus since the daughter nuclei produced has the same mass number and the atomic number increased by 1 i.e 14 7N

Please see the attached photo for more details

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3 years ago