<span>We never really used the acronym "IMA", or ideal mechanical advantage, but I'm assuming you are trying to increase the leverage and ease the effort. If so, the answer is false. You want larger movement on the effort side, and smaller movement on the resistant side of the fulcrum.</span>
They have to be warm because of the word thermic which means heat
Answer: 83.8 m/s
Explanation:
momentum of shell = momentum of cannon
M(s) × V(s) = M(c) × V(c)
M(s) = mass of shell, V(s) = velocity of shell
M(c) = mass of cannon, V(c) = velocity of cannon
100kg × 75m/s = 90kg × V(c)
7500 = 90 × V(c)
7500 ÷ 90 = V(c)
83.3 = V(c)
Answer:
1.9 m
Explanation:
78 m/s / (42 cycles/s) = 1.8571... m/cycle
Answer:
Explanation:
Conservation of momentum during the collision
0.023(230) + 2.0(0.0) = 0.023(170) + 2.0v
v = 0.69 m/s
The initial block kinetic energy will be converted to friction work
½mv² = Fd = μmgd
½(2.0)(0.69²) = 0.15(2.0)(9.8)d
d = 0.1619387... m
d = 16 cm
