Question

The nuclear equation is incomplete. Superscript 1 Subscript 1 Baseline H + Superscript 15 Subscript 7 Baseline N yields blank + Superscript 4 Subscript 2 Baseline H e What particle completes the equation? Superscript 12 Subscript 6 Baseline M g Superscript 11 Subscript 5 Baseline B Superscript 11 Subscript 5 Baseline N a Superscript 12 Subscript 6 Baseline C

Answer 1

Answer:

d. 12/6C

Explanation:

Answer 2

Answer:

The missing species is carbon-12 $^{12}_{\phantom{1}6}\mathrm{C}$.

The nuclear equation should be $^{1}_{1}\mathrm{H} + ^{15}_{\phantom{1}7}\mathrm{N} \to ^{12}_{\phantom{1}6}\mathrm{C} + ^{1}_{1}\mathrm{H}$.

Explanation:

Let $A$ represent the mass number of the missing species, and let $Z$ represent its atomic number.

$^{\;\;\;\text{Mass number \to A }}_{\text{Atomic number \to Z }}\mathrm{X}$.

For this question, there are three things to consider:

• The sum of the mass numbers should be conserved.
• Since there's no beta particle ($\rm e^{-}$ or $\mathrm{e}^{+}$) involved, the sum of the atomic numbers should also be conserved.
• The atomic number of the missing species should correspond to atomic symbol.

Mass Number

The sum of the mass numbers on the left-hand side of this reaction is: $1 + 15 = 16$.

The sum of the mass number on the right-hand side (including that of the missing species) is $(A + 4)$.

These two numbers should be the same. In other words, $A + 4 = 16$. Therefore, the mass number of the missing species would be $12$.

Atomic Number

The sum of the atomic numbers on the left-hand side of this reaction is: $1+ 7 = 8$.

The sum of the mass number on the right-hand side (including that of the missing species) is $(Z + 2)$.

These two numbers should be the same. In other words, $Z + 2 = 8$. Therefore, the mass number of the missing species would be $6$.

Symbol

The atomic number $Z$ of the missing species is $6$. Look up a modern periodic table. The element with atomic number