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jok3333 [9.3K]
3 years ago
12

A 90kg cannon fires 100kg shell with muzzle velocity of 75m/s. Calculate the recoil velocity of the cannon relative to the groun

d​
Physics
1 answer:
Gala2k [10]3 years ago
5 0

Answer: 83.8 m/s

Explanation:

momentum of shell = momentum of cannon

M(s) × V(s) = M(c) × V(c)

M(s) = mass of shell, V(s) = velocity of shell

M(c) = mass of cannon, V(c) = velocity of cannon

100kg × 75m/s = 90kg × V(c)

7500 = 90 × V(c)

7500 ÷ 90 = V(c)

83.3 = V(c)

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All the observers are correct.

Explanation:

This is simply a problem of reference frames from which the motion of the book is being viewed by the various observers.

From their various reference frames, they are all correct.

Observer A must be in the inertial reference frame.

<em>Observers who can explain the behavior of the book  and the car by using the relationship between the sum of  the forces and changing velocity are said to be observers in inertial reference frames.</em>

This is clearly shown by what observer A noticed. There was a relative motion between the book and the car as she pointed out, making her to be in an inertial reference frame.

<em>Similarly, observers in inertial reference frames can also explain the changes in velocity of objects  by considering the forces exerted on them by other objects.</em>

This is shown by observer B as he is able to notice how the force of the car affects the velocity of the book.

Observer C is actually in a non-inertial reference frame, as newtons law of force motion relationship are no longer observed. This occurs in the non inertial reference frame.

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2 years ago
Which model could represent a neutral atom of boron?
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3 years ago
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What is the equation for electric potential
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Metals in group 2 on the period table most commonly form which type
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A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
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Explanation:

Given that,

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We need to find the mass of the meter stick. The force acting by the stone is

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9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

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