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Readme [11.4K]
2 years ago
5

What is the energy of a photon with a frequency of 3. 6 Ă— 1015 Hz? Planck’s constant is 6. 63 Ă— 10â€""34 J•s. 1. 8 Ă— 10â€

""49 J 2. 4 Ă— 10â€""19 J 1. 8 Ă— 10â€""18 J 2. 4 Ă— 10â€""18 J.
Physics
1 answer:
erastovalidia [21]2 years ago
8 0

Every photon has some energy within it and that energy is called photon energy.

The energy of photon is 2.38\times10^{-18}\;\rm J.

Given that, frequency of the photon is 3.6\times10^{15}\;\rm Hz and Planck's constant is 6.626\times {{10}^{-34}}.

So the energy of the photon can be calculated by the given formula.

E=h\nu

Where h is plank's constant and \nu is the frequency of the photon.

By substituting the values in the above formula, the photon energy is,

E=6.626\times10^{-34}\times3.6\times10^{15}\;\rm J

E=2.38\times10^{-18}\;\rm J

The energy of photon is 2.38\times10^{-18}\;\rm J.

For more details about the energy of photon, follow the link given below.

brainly.com/question/15870724.

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Answer:

1) In a concave mirror parallel rays falling on it converges at F and 2F.

Explanation:

Spherical mirrors can be used for magnification of images. There are basically two types of spherical mirrors and they are converging mirror and diverging mirrors. The converging mirrors are also termed as concave mirrors and its basic work is to converge or combine light rays coming from a larger distance to a single point. Mostly the light beams falling parallel to the principle axis of the concave mirror will be acting as parallel rays. And when these parallel rays fall on the mirror, the converging point can be the focal point of the mirror.

Thus the location of converging point in concave mirrors will be based on the position or distance of object from the mirror. If the object distance is very far from the twice the focal length distance of mirror, then the converging point will be the focal point or F. And if the object is placed slightly greater than twice the distance of focal point, then the image will be obtained at 2F. But the parallel beams will be converging at F and 2F.

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A uniformly charged, straight filament 5.10 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder
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70509.8039216 N/C

Explanation:

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Electric field is given by

E=\dfrac{2k\lambda}{r}\\\Rightarrow E=\dfrac{2\times 8.99\times 10^9\times \dfrac{2\times 10^{-6}}{5.1}}{10\times 10^{-2}}\\\Rightarrow E=70509.8039216\ N/C

The electric field at the surface of the cylinder is 70509.8039216 N/C

7 0
3 years ago
Read 2 more answers
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natta225 [31]

Answer:

maybe it is the first one

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