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Readme [11.4K]
2 years ago
5

What is the energy of a photon with a frequency of 3. 6 Ă— 1015 Hz? Planck’s constant is 6. 63 Ă— 10â€""34 J•s. 1. 8 Ă— 10â€

""49 J 2. 4 Ă— 10â€""19 J 1. 8 Ă— 10â€""18 J 2. 4 Ă— 10â€""18 J.
Physics
1 answer:
erastovalidia [21]2 years ago
8 0

Every photon has some energy within it and that energy is called photon energy.

The energy of photon is 2.38\times10^{-18}\;\rm J.

Given that, frequency of the photon is 3.6\times10^{15}\;\rm Hz and Planck's constant is 6.626\times {{10}^{-34}}.

So the energy of the photon can be calculated by the given formula.

E=h\nu

Where h is plank's constant and \nu is the frequency of the photon.

By substituting the values in the above formula, the photon energy is,

E=6.626\times10^{-34}\times3.6\times10^{15}\;\rm J

E=2.38\times10^{-18}\;\rm J

The energy of photon is 2.38\times10^{-18}\;\rm J.

For more details about the energy of photon, follow the link given below.

brainly.com/question/15870724.

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The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the i
Nadya [2.5K]
Mechanical advantage = ideal mechanical advantage x efficiency = 3.5 x 0.6 = 2.1
The mechanical advantage of the inclined plane is 2.1

7 0
3 years ago
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

Explanation:

a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

mL²α/3 = mgL

dividing through by mL, we have

Lα/3 = g

multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

= 32.67 rad/s²

b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

5 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
a net force of 219 N is exterted on a rock. the rock has an acceleration of 3m/s^2 due to this force. what is the mass of the ro
Sonbull [250]

Answer:

<h2>73 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{219}{3}  \\

We have the final answer as

<h3>73 kg</h3>

Hope this helps you

6 0
2 years ago
One of the signs a chemical reaction is taking place
ladessa [460]

Answer:  One of the signs a chemical reaction is taking place is the presence of bubbles. :)

6 0
3 years ago
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