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3 years ago

7

Calculating dosages ch 4 if a satellite can travel 200 feet per second, how many hours will it take the satellite to travel 10,0

00 miles

1 answer:

Elanso [62]3 years ago

8 0

I do not have answer for this question looking for help.

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Multiple choice geomotry 1 question

atroni [7]

Answer:

c

Step-by-step explanation:

4 0

3 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

Katena32 [7]

Answer:

Margin of error = 0.196

Step-by-step explanation:

We are given that the manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customers to check out was 3 minutes. It is known that the standard deviation of the population of checkout times is 1 minute.

That means; Sample size, n = 100

Population standard deviation = 1 minute

Sample mean = 3 minutes

Now, the Margin of error means how much deviation is there from the sample mean to calculate the confidence interval for true population mean.

Margin of error formula is given by = $Z_\frac{\alpha}{2} \times \frac{\sigma}{\sqrt{n} }$

where, $\sigma$ = population standard deviation

n = sample size of customers

$\alpha$ = significance level = 5%

Now, the z probability area at 5% significance level is given to be 1.96 from z table.

So, Margin of error = $1.96 \times \frac{1}{\sqrt{100} }$ = $\frac{1.96}{10}$ = 0.196 .

Therefore, with a .95 probability, the sample mean will provide a margin of error of 0.196 .

7 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.

xz_007 [3.2K]

Answer:

Part 1) $f(x)=\frac{2x-1}{x+2}$ -------> $f^{-1}(x)=\frac{-2x-1}{x-2}$

Part 2) $f(x)=\frac{x-1}{2x+1}$ -------> $f^{-1}(x)=\frac{-x-1}{2x-1}$

Part 3) $f(x)=\frac{2x+1}{2x-1}$ -----> $f^{-1}(x)=\frac{x+1}{2(x-1)}$

Part 4) $f(x)=\frac{x+2}{-2x+1}$ ----> $f^{-1}(x)=\frac{x-2}{2x+1}$

Part 5) $f(x)=\frac{x+2}{x-1}$ -------> $f^{-1}(x)=\frac{x+2}{x-1}$

Step-by-step explanation:

Part 1) we have

$f(x)=\frac{2x-1}{x+2}$

Find the inverse

Let

y=f(x)

$y=\frac{2x-1}{x+2}$

Exchange the variables x for y and t for x

$x=\frac{2y-1}{y+2}$

Isolate the variable y

$x=\frac{2y-1}{y+2}\\ \\ xy+2x=2y-1\\ \\xy-2y=-2x-1\\ \\y[x-2]=-2x-1\\ \\y=\frac{-2x-1}{x-2}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{-2x-1}{x-2}$

Part 2) we have

$f(x)=\frac{x-1}{2x+1}$

Find the inverse

Let

y=f(x)

$y=\frac{x-1}{2x+1}$

Exchange the variables x for y and t for x

$x=\frac{y-1}{2y+1}$

Isolate the variable y

$x=\frac{y-1}{2y+1}\\ \\2xy+x=y-1\\ \\2xy-y=-x-1\\ \\y[2x-1]=-x-1\\ \\y=\frac{-x-1}{2x-1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{-x-1}{2x-1}$

Part 3) we have

$f(x)=\frac{2x+1}{2x-1}$

Find the inverse

Let

y=f(x)

$y=\frac{2x+1}{2x-1}$

Exchange the variables x for y and t for x

$x=\frac{2y+1}{2y-1}$

Isolate the variable y

$x=\frac{2y+1}{2y-1}\\ \\2xy-x=2y+1\\ \\2xy-2y=x+1\\ \\y[2x-2]=x+1\\ \\y=\frac{x+1}{2(x-1)}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x+1}{2(x-1)}$

Part 4) we have

$f(x)=\frac{x+2}{-2x+1}$

Find the inverse

Let

y=f(x)

$y=\frac{x+2}{-2x+1}$

Exchange the variables x for y and t for x

$x=\frac{y+2}{-2y+1}$

Isolate the variable y

$x=\frac{y+2}{-2y+1}\\ \\-2xy+x=y+2\\ \\-2xy-y=-x+2\\ \\y[-2x-1]=-x+2\\ \\y=\frac{-x+2}{-2x-1} \\ \\y=\frac{x-2}{2x+1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x-2}{2x+1}$

Part 5) we have

$f(x)=\frac{x+2}{x-1}$

Find the inverse

Let

y=f(x)

$y=\frac{x+2}{x-1}$

Exchange the variables x for y and t for x

$x=\frac{y+2}{y-1}$

Isolate the variable y

$x=\frac{y+2}{y-1}\\ \\xy-x=y+2\\ \\xy-y=x+2\\ \\y[x-1]=x+2\\ \\y=\frac{x+2}{x-1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x+2}{x-1}$

7 0

3 years ago

Use the grouping method to factor the polynomial below completely.

RSB [31]

The correct answer is D

5 0

3 years ago

A fish population grew according to the following quadratic model, the number of fish a day is given by

Blizzard [7]

Answer: -200

<u>Step-by-step explanation:</u>

P(t) = 800t - t²

P(600) = 800(600) - (600)²

= 480,000 - 360,000

= 120,000

P(400) = 800(400) - (400)²

= 320,000 - 160,000

= 160,000

$\text{rate of change}=\dfrac{P(600)-P(400)}{600-400}=\dfrac{120,000-160,000}{200}=\dfrac{-40,000}{200}=-200$

7 0

3 years ago