4 x^2 + 20 x + 25 = 7
Divide both sides by 4:
x^2 + 5 x + 25/4 = 7/4
Write the left-hand side as a square:
(x + 5/2)^2 = 7/4
Take the square root of both sides:
x + 5/2 = sqrt(7)/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
x = sqrt(7)/2 - 5/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
Answer: x = sqrt(7)/2 - 5/2 or x = -5/2 - sqrt(7)/2
Since

is negative, it doesn't have any real roots.
The options are not provided, but method is stated below
Answer:
Quadratic equation ax2 - 6x + c = 0
options would be given for a and c
- substitute a and c
- check for Discriminant
-
- 36 -4ac
These conditions will fetch us the result required among the options.
Note : the
sign will give us the result for Two real unequal solutions and two real equal solutions. If we only need Real unequal solutions we only use > sign instead of