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Vadim26 [7]
3 years ago
11

A portion of the Quadratic Formula proof is shown. Fill in the missing statement. x equals b plus or minus the square root of b

squared minus 4 times a times c, all over 2 times a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x plus b over 2 times a equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

Mathematics
2 answers:
liraira [26]3 years ago
8 0

Answer:  x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

<u>Step-by-step explanation:</u>

When you subtract b/2a from both sides, you end up with the Quadratic Formula.

natima [27]3 years ago
7 0

Answer:

\displaystyle x=\frac{-b \± \sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

\displaystyle x+\frac{b}{2a} =\±\frac{\sqrt{b^2-4ac} }{2a}

Subtract \frac{b}{2a} from both sides.

\displaystyle  x+\frac{b}{2a} -\frac{b}{2a} =\±\frac{\sqrt{b^2-4ac} }{2a}-\frac{b}{2a}

\displaystyle  x=\frac{ \± \sqrt{b^2-4ac} -b}{2a}

\displaystyle  x=\frac{-b \± \sqrt{b^2-4ac} }{2a}

This is a quadratic formula.

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[(8*9)] - (6*7)] -15
maks197457 [2]

Answer:

15

Step-by-step explanation:

Simplify the following:

8×9 - 6×7 - 15

8×9 = 72:

72 - 6×7 - 15

-6×7 = -42:

72 + -42 - 15

72 - 42 - 15 = 72 - (42 + 15):

72 - (42 + 15)

| 4 | 2

+ | 1 | 5

| 5 | 7:

72 - 57

| 6 | 12

| 7 | 2

- | 5 | 7

| 1 | 5:

Answer:  15

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levacccp [35]
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(4x-y=-15)<br>(3x-2y=-10)<br>​
Andreyy89

Answer:

<h2>x = -4 and y = -1 → (-4, -1)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}4x-y=-15&\text{multiply both sides by (-2)}\\3x-2y=-10\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-8x+2y=30\\3x-2y=-10\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-5x=20\qquad\text{divide both sides by (-5)}\\.\qquad\qquad\boxed{x=-4}\\\\\\\text{Put the value of x to the first equation.}\\\\4(-4)-y=-15\\-16-y=-15\qquad\text{add 16 to both sides}\\-y=1\qquad\text{change the signs}\\\boxed{y=-1}

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