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Goshia [24]
2 years ago
6

DOES ANYONE UNDERSTAND QUADRATIC APPLICATIONS FOR ALGEBRA 1???? PLS DONT RESOND IF YOU DINT KNOW

Mathematics
1 answer:
lilavasa [31]2 years ago
4 0

Answer:

1 ) Vertex form.

2 ) Standard form.

3 ) I'm not sure about this one, but there are only 3 forms, in which the last one is factored form, and the other two are above, so it must be factored form.

Step-by-step explanation:

1 ) Vertex form : y = a( x - h )² + k

Vertex form shows you where the vertex(the lowest/highest point aka ( h, k ) ) of the parabola is, without graphing it. (But you could graph it and find the vertex like that, I recommend you use desmos graphing)

2 )Standard form : y = ax² + bx + c

Standard form can be used to show the y-intercept( aka c ), in this case, where the snowball was thrown from. (Again, you can graph it and find where he parabola hits the y axis)

3 ) Factored form : ( ax + c )( bx + d )

Factored form tells us the x-intercepts, or in this case where the snowball landed or how long the snowball is in the air. (like i said, you could graph it, and find the points(there could be only one or maybe none in some cases) that are on the x axis)

I know this was four days ago, but I hope this helped you understand a little better.

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Find the midpoint of segment JT when the coordinates are J(-3,18) and T(7,-10). Show all work
nignag [31]
Given two points (x₁,y₁) and (x₂,y₂), the midpoint of the segment will be:
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The midpoint will be:
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lora16 [44]

Answer:

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If both the top an bottom are equal, you know that 150 degres are taken (75+75) and you know that there can only be 360 degres in total here, so you subtract 150 from 360 and get 210. Now you know that the last two sides together are 210, and since they are equal, you divide it by two to get 105 degrees.

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