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3 years ago

Number 13 explain......

Mathematics

1 answer:

Marat540 [252]3 years ago

3 0

The slope is 2 and the equation of the line is y = mx+b with m =2

Then the equation becomes: y = 2x+b. How to calculate b?
Since this line passes through the point (-3 , 4), we replace x with -3 and y=4

4= 2.(-3) + b
4 = - 6 + b
and b= 10. The final equation is : y = 2x + 10 (answer a)

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The cost of 1 dozen pencil is Rs.96.what is the cost of 2 pencils

natali 33 [55]

Answer:

Rs.16

Step-by-step explanation:

Divide the cost of Rs.96 by 12 then multiply by 2

cost of 1 pencil = Rs.96 ÷ 12 = Rs.8

cost of 2 pencils = 2 × Rs.8 = Rs.16

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2 years ago

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What is 3/15 in a decimal

Damm [24]

Well, since 3/15 can be simplified to 1/5 by dividing the top and the bottom by 3, you would just need to find the decimal of 1/5 which is much more commonly recognized. it's .2 (becasue 1/10 would be .1 and 1/5=2/10 so .1x2=.2)

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3 years ago

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3+-√(-3)^2 - 4(5)(-1)

Alona [7]

Answer:

Step-by-step explanation:

Easy way to do this is step by step. Your quadratic, from your entry, must be

$5x^2-3x-1$ .

Step by step looks like this, one thing at a time:

$x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)}$ becomes

$x=\frac{3+\sqrt{9-(-20)} }{10}$ becomes

$x=\frac{3+\sqrt{9+20} }{10}$

and this of course is

$x=\frac{3+\sqrt{29} }{10}$

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign. If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

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3 years ago

Solve for x: 2x^2 + 3x = 2 <br>solving other quadratic equation by factoring

DIA [1.3K]

Answer: x=1/2,-2

not sure if that is what you need

Step-by-step explanation:

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3 years ago

If you knew that f(-4)=8, then what (x,y) coordinate point must lie on the graph of y=f(x)?

AysviL [449]

I believe it would be (-4, 8); because when x = -4, y = f(x) = 8.

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