What is static electricity? explain how electrons are involved please answer asap

Physics

1 answer:

anastassius [24]3 years ago

4 0

Answer:

Electricity produced via friction is a development of electric charges on articles. Energizes construct when negative electrons are moved starting with one article then onto the next. The article that surrenders electrons turns out to be decidedly charged, and the item that acknowledges the electrons turns out to be contrarily charged. This can occur in a few different ways.

Explanation:

$\mathrm {All, done!}$

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The following problem presents hypothetical values. In the diagram below, the synodic period (one lunar month) is given as 30 da

balu736 [363]

Answer:

x is approximately 95.495

Explanation:

The given information are;

One lunar month = 30 days

The measured time between the first and third quarters = 14.9 days

Therefore, the angle of rotation for 30 days = 360°

The angle of rotation for 14.9 days = 14.9×360/30 = 178.8°

Therefore, whereby 2·θ = 178.8°

θ = 178.8°/2 = 89.4°

Therefore, given that the angle at the tangent from Sun to the Moon = 90°, we have;

The angle between the line from the Sun to the Moon = 90° - 89.4° = 0.6°

From sine rule, we have;

1/(sin 0.6) = x/(sin 90°)

x = (sin 90°)/(sin 0.6°) ≈ 95.495

x = 95.495.

6 0

3 years ago

A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19

IRISSAK [1]

Answer:

128 is the ans cuz N is also lnown as mass

Explanation:

128

6 0

3 years ago

Suatu sistem gas berada didalam ruang yang fleksibel. Pada awalnya gas berada pada kondisi P1 = 1,5 × 10 pangkat 5 N/m2, T1 = 27

enot [183]

Answer:

16.00L

Explanation:

First you calculate the number of moles in the system:

$PV=nRT\\\\n=\frac{PV}{RT}\\\\n=\frac{(1.5*10^5N/m^2)(12L)}{(0.082L.atm/mol.K)(300.15K)}=73134.16\ mol$

To find the new volume of the system you use the following formula for an isobaric procedure:

$T_2-T_1=\frac{P}{nR}(V_2-V_1)\\\\V_2=\frac{nR}{P}(T_2-T_1)+V_1\\\\V_2=\frac{(73134.16\ mol)(0.082L.atm/mol.K)}{1.5*10^5N/m^2}(400.15-300.15)K+12L\\\\V_2=16.00L$