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goldfiish [28.3K]
4 years ago
10

How does sound intensity differ from loudness?

Physics
1 answer:
Artyom0805 [142]4 years ago
6 0

Answer:

Sound intensity is the amount of energy carried by sound versus loudness is a subjective measurement of the audible sound.

Sound intensity is measured in watt per square meter where loudness is measured in sones (sone is a subjective measurement and not an SI unit)

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A rod 25 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its le
Airida [17]

Answer:

v = 666.667 m/s

Explanation:

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Solution:

emf = vBL

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x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\&#10;y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
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0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\&#10;m_2v_2sin(\theta)=m_1v_1'sin(34)\\&#10;sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\&#10;\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})
When we plug all the number we get:
\theta=27.45^\circ
Please note that this is the angle below the x-axis.

6 0
3 years ago
The first formal laboratory for research in psychology was established by B.F. skinner
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*** B.F Skinner is known for inventing the operant conditioning chamber. ***
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\frac{v}{t}
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or
a  =  \frac{f}{m}
6 0
3 years ago
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