Answer:
we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different
Explanation:
Natural frequency of a simple pendulum of L length is given as
so the time period of the oscillation is given as
so we will have
also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different
Answer:
4.4 seconds
Explanation:
Given:
a = -5.5 m/s²
v₀ = 0 m/s
y₀ = 53 m
y = 0 m
Find: t
y = y₀ + v₀ t + ½ at²
0 = 53 + 0 + ½ (-5.5) t²
0 = 53 − 2.75 t²
t = 4.39
Rounded to two significant figures, it takes 4.4 seconds for the object to land.
Answer:
The mass of G1 at all times during this trial was <u>0.5</u> kg.
The velocity of G1 + G2 after the collision was <u>-1.24</u> m/s.
The momentum of G1 after the collision was <u>-2.10</u> kg · m/s.
Explanation:
i got it right
