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salantis [7]
3 years ago
13

PLEASE HELP!! DUE SOON!!!

Physics
2 answers:
Alecsey [184]3 years ago
7 0
The answer is D, all responses are correct
aliya0001 [1]3 years ago
4 0
The answer is D I’m sorry if I’m incorrect
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Which factors improve soil fertility? Select the three correct answers. A. Humus B. Bedrock C. Horizon D. Nitrogen E. Manure
Katyanochek1 [597]

Correct answer choices are :

A) Humus

E) Manure

D) Nitrogen


Explanation:


Soil fertility leads to the capability of a soil to support agricultural plant growth, i.e. to produce plant environment and occur in continued and steady yields of high quality. A fertile soil will include all the important nutrients for basic plant nourishment, as well as other nutrients required in smaller amounts.

5 0
4 years ago
Read 2 more answers
soaring birds and glider pilots can remain aloft for hours without expending power. Discuss why this is so.
vekshin1

Answer:

Since their wings and body develop the drag. When there is warm air then they expand their wings. Since,soaring birds and glider pilots have no engine, they always maintain their high speed to lift their weight in air for hours without expending power by convection

Explanation:

5 0
3 years ago
How many atoms are present in 3 molecules of chromium
iren2701 [21]
Answer:

1,8066 x 1024 atoms

Explanation:

1 mole of chromium contains 6,022 x 1023 atoms

so

3 moles of chromium contains 3 times as many atoms

3 x 6,022 x 1023 = 1,8 066 x 1024

5 0
4 years ago
Sally accelerates a 250 kg cart at 3 m/s/s. What must be
Arisa [49]
Net force = mass x acceleration = 250 x 3 = 750 N
3 0
3 years ago
A thin spherical shell with radius R1 = 4.00 cm is concentric with a larger thin spherical shell with radius R2 = 6.00 cm . Both
kakasveta [241]

Answer:

The right response will be "450 volts".

Explanation:

The given values are:

R1 = 4.00 cm

R2 = 6.00 cm

q1 = +6.00 nC

q2 = −9.00 nC

As we know,

The potential difference between the two shell's difference will be:

⇒  \Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]

           =K[\frac{q1}{R2}-\frac{q1}{R1} ]

On substituting the values, we get

           =(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]  

       Δ =450 \ volts

3 0
3 years ago
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