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Sergio [31]
2 years ago
7

Can someone help with these questions (1 , 3 , 4)

Physics
1 answer:
LenaWriter [7]2 years ago
8 0

Remark

4 is long (but not hard) and I am in a terrible time bind. I will take a short at doing it but it will be abbreviated.

One

Ax = 70*cos(51.7) = 43.38

Ay = 70*sin(51.7) = 54.93

That makes C the correct answer. To resolve these, Ax is always taken along the +x axis. and Ay is always associated with the y axis. A(x) always uses Cos(x) and Ay = sin(x)

Three

A would be true if Ax and Ay were vectors. They don't seem to be. They look like scalers. Magnitudes don't add that way.

B Theta = tan-1(Ay/Ax) The Statement given is simply not true.

C Tan(Theta) = Ay / Ax Not The given result

D is correct Cos(theta) = The magnitude along the +x axis divided by the hypotenuse which is sqrt(Ax^2 + Ay^2)

Four

The best way to do this is to set up x and y values in a table. I can't do this well, but I'll try.

<u>x</u>                                                            <u>y</u>

12*cos(53) = 7.22                             15*sin(53)= 9.58

15*cos(-40) = <u>11.49</u>                            15.sin(-40) = <u>-9.64</u>

Sum =            18.69                                             = - 0.08

As you can see most of the magnitude and direction will come from Ax

So the answer is 19 for the magnitude and 0o for the direction. The other choices are taken from theta = 40o. That minus sign makes all the difference.          

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A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike rider is 91kg. What is the kinetic energy of
Anestetic [448]

a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

KE = \frac{1}{2}m* v^{2}

It is given:

v = 8.5 m/s

m = 91 kg

So:

KE= \frac{1}{2}*91*8.5^{2} =3,287.4J


b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h

In this case, h is eight, and PE is the same as KE:
PE = KE = 3,287.4 J

m = 91 kg

g = 9.81 m/s² - gravitational acceleration

h = ? - height


Now, let's replace those:

3,287.4= 91 * 9.81 * h

⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m

3 0
3 years ago
You and your lab partner, Mel, are engrossed in a chemistry activity using beans to compute the average atomic mass of an elemen
Vikentia [17]

Answer:

C:

Explanation:

either C or A but A seems unlikely after multiple attempts. Although the question doesn't make it clear whether the balance is electric either way it could be wrong in someway and seems to be the most likely.

5 0
3 years ago
Read 2 more answers
Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass
Gala2k [10]

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

\Delta W = \Delta PE + \Delta KE

Where,

PE = Potential Energy

KE = Kinetic Energy

\Delta W = (\Delta m)gh+\frac{1}{2}(\Delta m)v^2

Where,

m = Mass

g = Gravitational energy

h = Height

v = Velocity

Considering power as the change of energy as a function of time we will then have to

P = \frac{\Delta W}{\Delta t}

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

The rate of mass flow is,

\frac{\Delta m}{\Delta t} = \rho_w Av

Where,

\rho_w = Density of water

A = Area of the hose \rightarrow A=\pi r^2

The given radius is 0.83cm or 0.83 * 10^{-2}m, so the Area would be

A = \pi (0.83*10^{-2})^2

A = 0.0002164m^2

We have then that,

\frac{\Delta m}{\Delta t} = \rho_w Av

\frac{\Delta m}{\Delta t} = (1000)(0.0002164)(5.4)

\frac{\Delta m}{\Delta t} = 1.16856kg/s

Final the power of the pump would be,

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

P = (1.16856)((9.8)(3.5)+\frac{1}{2}5.4^2)

P = 57.1192W

Therefore the power of the pump is 57.11W

6 0
3 years ago
I need help with question 2 and 2 please
vitfil [10]
Alright here the answer to number 2

5 0
3 years ago
Please help it’s urgent
Sidana [21]

Answer:

I believe it's sound energy.

Explanation:

Sound can move through air, whereas electric and radiant energy don't have to.

6 0
3 years ago
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