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4 years ago

Which factors improve soil fertility? Select the three correct answers. A. Humus B. Bedrock C. Horizon D. Nitrogen E. Manure

Physics

2 answers:

Katyanochek1 [597]4 years ago

5 0

Correct answer choices are :

A) Humus

E) Manure

D) Nitrogen

Explanation:

Soil fertility leads to the capability of a soil to support agricultural plant growth, i.e. to produce plant environment and occur in continued and steady yields of high quality. A fertile soil will include all the important nutrients for basic plant nourishment, as well as other nutrients required in smaller amounts.

alisha [4.7K]4 years ago

4 0

<h3>Answer;</h3>

Humus
Manure
Nitrogen

<h3>Explanation;</h3>

Soil fertility is a characteristic of soil that refers to the capability of soil to maintain and provide a suitable habitat for growth of agricultural crops, thus resulting to continuous productivity.
The fertility of soil may be influenced or enhanced by various factors which includes, the soil structure, organic matter, soil pH, and water retention among other factors.
Humus, nitrogen, and manure are among the factors that boosts or improves soil fertility, and thus enhances growth and sustainability of agricultural crops by the soil.

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Answer: $2.04\times 10^{-5}/K$

Explanation:

Given

initial volume $V_0=1000 cm^3$

initial Temperature $T_i=0.3^{\circ}C$

Final Temperature $T_f=52^{\circ}C$

Volume of overflow of mercury $=8.25 cm^3$

We know volume expansion of Mercury $\beta _{Hg}=1.80\times 10^{-4} /K$

Volume Expansion of Mercury

$V_f=V_0(1+\beta _{Hg}\Delta T)$

$V_f=1000(1+1.80\times 10^{-4}\times 51.7)$

$V_f=1009.306 cm^3$

therefore volume Expansion of flask

$V_f-8.25=1009.306-8.25=1001.056 cm^3$

Volume Expansion of Glass

$V_f'=V_0(1+\beta _{glass}\Delta T)$

$1001.056=1000(1+\beta _{glass}\times 51.7)$

$1.001056=1+\beta _{glass}\times 51.7$

$\beta _{glass}\times 51.7=0.001056$

$\beta _{glass}=\frac{0.001056}{51.7}=2.04\times 10^{-5}/K$

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4 years ago

1. What is the momentum of a 0.15 kg arrow that is traveling at 120 m/s?

Korvikt [17]

For this case we have that by definition, the momentum equation is given by:

$p = m * v$

Where:

m: It is the mass

v: It is the velocity

According to the data we have:

$m = 0.15 \ kg\\v = 120 \frac {m} {s}$

Substituting:

$p = 0.15 * 120\\p = 18 \frac {kg * m} {s}$

On the other hand, if we clear the variable "mass" we have:

$m = \frac {p} {v}$

According to the data we have:

$p = 250 \frac {kg * m} {s}\\v = 5 \frac {m} {s}\\m = \frac {250} {5}\\m = 50 \ kg$

Thus, the mass is $50 \ kg$

Answer:

$p = 18 \frac {kg * m} {s}\\m = 50 \ kg$

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3 years ago

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Answer:

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Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.

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