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MatroZZZ [7]
3 years ago
7

Your grandfather clock's pendulum has a length of 0.9930 m. if the clock loses 60 seconds per day, should you increase or decrea

se the length of the pendulum?
Physics
2 answers:
wel3 years ago
4 0
We have to speed up the watch so we need to decrease time period of pendulum. So we hv to reduce the length.
ser-zykov [4K]3 years ago
4 0

Answer:

Pendulum should be decreased to 0.9914m

Explanation:

The clock losses 60seconds per day.

In a day,there are 24×60×60=86400seconds/day

The period T= 2pisqrt(L/g)

T= 2×3.142sqrt(0.9930/9.8)

T= 2.00005277seconds

Error ratio=60/86400= 6.94×10^-4

Terror= 2.00005277×6.94×10^-4=1.389×10^-3seconds

Tcorrect=Toriginal -T error

Tcorrect= 2.00005277- 1.389×10^-3=1.998seconds

T=2pisqrt(L/g)

Solving for L

T/2pi = sqrt(L/g)

T^2/(2pi)^2=(L/g)

L =( g× T^2) / (2pi)^2

L= (9.8×(1.9987)^2/(2×3.142)^2

L = 39.188/39.4887

L = 0.9914m

Pendulum should be decreased to 0.9914m.

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The relation between temperature and pressure is called the "equation of state of the gas". or "Hydrostatic equilibrium in ordinary star". Take for example a balloon, it will have a larger spherical shape, if the pressure inside exerted by the gas on a wall of a balloon balance the inward force exerted by the outside atmospheric pressure.  In a dying star which is being compressed by gravity, the gas is being squeezed so the molecules is moving rapidly, resulting to a very high temperature, and this provide a balance that counteract or balances the compressive force of gravity. The very high temperature inside the star is needed to balance the force of gravity, and it is provide by "nuclear fusion energy" or else the star would collapse under the force of gravity. Depending on the size or mass of the star, it will either become, a "neutron star" or a "black hole".                 
5 0
3 years ago
Read 2 more answers
A(n) _______ is a point level measuring system consisting of a circuit of two or more probes or electrodes, or an electrode and
Digiron [165]

Answer:

Conductivity probe

Explanation:

The Conductivity Probe consists of two electrodes(also referred to as probes)or an electrode and a wall vessel where the material in the vessel completes the circuit as the level rises in the vessel.

It is used in measuring solution conductivity or total ionic concentration of aqueous samples.

6 0
3 years ago
I. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maxi
nalin [4]

Answer:

Negative

Explanation:

If the box is heading right in the positive direction, the work will be negative. The spring has an opposite force to that of the box.

Hope this helped. :)

6 0
3 years ago
Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s
Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{40}{5}  \\

We have the final answer as

<h3>8 kg</h3>

Hope this helps you

7 0
3 years ago
A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 4.444 N
Dmitriy789 [7]

Answer:

The value of third charge is 0.8μC.

Explanation:

Given that.

Magnitude of net force=4.444 N

According to figure,

Suppose, First charge = 2.4 μC

Second charge = 6.2 μC

Distance r₁ = 9.8 cm

Distance r₂ = 2.1 cm

We need to calculate the value of r

Using Pythagorean theorem

r=\sqrt{(r_{1})^2+(r_{2})^2}

Put the value into the formula

r=\sqrt{(9.8)^2+(2.1)^2}

r=10.02\ cm

We need to calculate the force

Using formula of force

F_{12}=\dfrac{kq_{1}q_{2}}{(r)^2}

Force F₁₂,

F_{12}=\dfrac{9\times10^{9}\times2.4\times10^{-6}\times6.2\times10^{-6}}{(10.02\times10^{-2})^2}

F_{12}=13.33\ N

F_{21}=-13.33\ N

Force F₂₃,

F_{23}=\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(10.02)^2}

We need to calculate the value of third charge

F_{net}=F_{21}+F_{23}

4.444=-13.33+\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(5.01)^2}

q_{3}=\dfrac{(4.444+13.33)\times(5.01\times10^{-2})^2}{9\times10^{9}\times6.2\times10^{-6}}

q_{3}=7.99\times10^{-7}\ C

q_{3}=0.8\times10^{-6}\ C

Hence, The value of third charge is 0.8μC.

4 0
3 years ago
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