Answer
given,
v = (6 t - 3 t²) m/s
we know,


position of the particle

integrating both side

x = 3 t² - t³
Position of the particle at t= 3 s
x = 3 x 3² - 3³
x = 0 m
now, particle’s deceleration


a = 6 - 6 t
at t= 3 s
a = 6 - 6 x 3
a = -12 m/s²
distance traveled by the particle
x = 3 t² - t³
at t = 0 x = 0
t = 1 s , x = 3 (1)² - 1³ = 2 m
t = 2 s , x = 3(2)² - 2³ = 4 m
t = 3 s , x = 0 m
total distance traveled by the particle
D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s
D = 2 + 4 + 2 = 8 m
average speed of the particle



Answer:
Its C
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<span>B. equal and in opposite directions</span>
Answer:

Explanation:
If there is a dielectric slab with thickness less than the distance between the plates is inserted inside a capacitor, then that capacitor can be regarded as two capacitors connected in series.
Let's assume that the slab is placed onto the lower side. So, the capacitance of that part of the capacitor, C1 is

where
is the permittivity of the slab.
The other part of the capacitor is

Two capacitors are connected in series:

If we know the charge of the plates, we could relate the potential V0 to capacitance via

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