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gavmur [86]
2 years ago
8

What is the maximum amount of energy that could be produced from the reaction of 85.0 grams of Aluminum with 95.0 grams of oxyge

n, according to the following reaction?
4 Al + 3 O2 = 2 Al2O3 AHH = -3352 kJ
Chemistry
1 answer:
Tom [10]2 years ago
5 0

Answer:

47 kj

Explanation:

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Use the information to answer the following question.
jolli1 [7]
I think the answer is c
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He following balanced equation shows the formation of water. 2H2 + O2 mc020-1.jpg 2H2O How many moles of oxygen (O2) are require
mrs_skeptik [129]

Answer : The correct option is, 13.7 mole

Solution : Given,

Moles of H_2 = 27.4 moles

The given balanced chemical reaction is,

2H_2+O_2\rightarrow 2H_2O

From the balanced chemical reaction, we conclude that

As, 2 moles of H_2 react with 1 moles of O_2

So, 27.4 moles of H_2 react with \frac{27.4}{2}=13.7 moles of O_2

Therefore, the number of moles of oxygen O_2 required are, 13.7 moles

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2 years ago
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If you collect 1.75 L of hydrogen gas during a lab experiment when the room temperature is 23oC and the barometric pressure is 1
ziro4ka [17]

Answer:

n=0.0747mol

Explanation:

Hello,

In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:

PV=nRT

Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:

n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol

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8 0
2 years ago
How do waves affect matter they are traveling through?
s344n2d4d5 [400]
The energy of the wave does not move through anything
4 0
3 years ago
calculate the volume that will be occupied by 350 ml of oxygen measured at 720 mm hg, when the pressure changed to 630 mm hg
likoan [24]

Answer:

406.45mL

Explanation:

The following data were obtained from the question:

V1 = 350mL

P1 = 720mmHg

P2 = 630mmHg

V2 =?

The new volume can be obtain as follows:

P1V1 = P2V2

720 x 350 = 620 x v2

Divide both side by 620

V2 = (720 x 350) /620

V2 = 406.45mL

The new volume of the gas is 406.45mL

8 0
3 years ago
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