Answer:
CH3COO-
Explanation:
The conjugate base if a weak acid is a strong base, and the conjugate base of a strong acid is a weak base.
Acetic acid is a weak acid, so its conjugate base (CH3COO-) is a strong base.
Nitric, sulfuric, and hydrochloric acids are all strong acid. Their conjugate bases (NO3-, SO4^2-, and Cl- are all weak bases.
Answer:
Explanation:
The equation is given as:
CH3CHOHC2H4CHO + CH3OH --> CYCLIC ACETAL + H2O
This above equation is carried out in the presence of a strong acid. There are five mechanisms employed and they are:
Step 1:
Initial formation of the hemiacetal which takes several steps
Step 2:
Addition of a proton. The hemicetal is protonated on the hydroxyl group (-OH group)
Step 3:
As seen a bond is broken to give the H2O molecule and a resonance stabilized cation.
The carbonyl group on the cation is enriched with the oxygen-18 got from the H2O molecule as seen in the mechanism.
Step 4:
An attraction occurs between electrophile and nucleophile i.e the stabilised cation and the lone paids of the methanol.
Step 5:
Finally, a proton (+) is removed from the molecule by a lone pair of electron on the methanol.
Attached are the Steps 1 - 5 mechanism below
D the chemical energy in a batery changes to electrical when its used
He was working with electrons