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MAVERICK [17]
3 years ago
13

What is the initial material of hydraulic lime?

Chemistry
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

The raw material of hydraulic lime is a limestone.

Such type of limestone is called <em>Argillaceus</em><em>.</em><em> </em>

<em>From</em><em>~</em><em>C</em><em>h</em><em>a</em><em>r</em><em>m</em><em>i</em><em>n</em><em>g</em><em>l</em><em>e</em><em>x</em><em>~</em>

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Maggie is sitting at a table wit Fred and Florence.Maggie has 10 markers but Fred and Florence each have only 7 markers.how can
Dima020 [189]

Answer:

Give them each one so all of you is 8

Explanation:

I hope it helps:)

6 0
3 years ago
Read 2 more answers
Barbiturates, including "truth serums" seen in movies like Meet the Fockers and sedatives that may have led to the untimely deat
Naya [18.7K]

Answer:

Explanation:

Diethyl malonate is more acidic than monocarbonyl compounds (pKa=13) due to their alpha hydrogens being attached to two carbonyl groups. Thus, the <u>malonic ester is easily converted to its enolate ion by reaction with sodium ethoxide in ethanol</u>. The product of the alkylation of the malonic ester leaves a <u>hydrogen atom acid in an alpha position</u>, so the alkylation process can be repeated a second time to produce a dialkylated malonic ester.

In this case, when urea is treated with diethyl malonate in the presence of sodium ethoxide base,<u> the second alkylation step occurs intramolecularly</u> to generate a cyclic product, barbituric acid.

8 0
3 years ago
Examining the figure, how many orders of magnitude larger is a person than a bacterial cell?
Allushta [10]
Well you did not show the figure, but I can show you how to do it.

Suppose the person is 6 feet tall and the bacteria cell is 1 micrometer in length.

So, put both magnitudes in the same units. I will use meter.

Person: 6 feet * 0.3048 m / foot = 1.8288 m, which in orders of magnitud is about 2 m

Bacteria cell: 1 micrometer * 1 m / 1,000,000 micrometer = 1 * 10 ^ -6 m.

Now divide: 2m / 10^ -6 m = 2,000,000

So a person is about 2 million times larger than a bacteria cell.

If the numbers in your figure are different you can use the same method to get a new result according to your figure.
8 0
3 years ago
An acetate buffer solution is prepared by combining 50. mL of a 0.20 M acetic acid, HC2H3O2 (aq), and 50. mL of 0.20 M sodium ac
Gala2k [10]

Answer:

B. CH3COOH pH > 4.7 (4.8)

Explanation:

  • CH3COOH + NaOH ↔ CH3COONa + H2O
  • CH3COONa + NaOH ↔ CH3COONa

∴ mol NaOH = (5 E-3 L)*(0.10 mol/L) = 5 E-4 mol

⇒ mol CH3COOH = (0.05 L)*(0.20 mol/L) = 0.01 mol

⇒ <em>C</em> CH3COOH = (0.01 mol - 5 E-4 mol) / (0.105 L)

⇒ <em>C</em> CH3COOH = 0.0905 M

∴ mol CH3COONa = (0.05 L )*(0.20 mol/L) = 0.01 mol

⇒ <em>C</em> CH3COONa =  (0.01 mol + 5 E-4 mol) / (0.105 L )

⇒ <em>C</em> CH3COONa = 0.1 M

∴ Ka = ([H3O+]*(0.1 + [H3O+])) / (0.0905 - [H3O+]) = 1.75 E-5

⇒ 0.1[H3O+] + [H3O+]² = (1.75 E-5)*(0.0905 - [H3O+])

⇒ [H3O+]² 0.1[H3O+] = 1.584 E-6 - 1.75 E-5[H3O+]

⇒ [H3O+]² + 0.1000175[H3O+] - 1.584 E-6 = 0

⇒ [H3O+] = 1.5835 E-5 M

∴ pH = - Log [H3O+]

⇒ pH = - Log (1.5835 E-5)

⇒ pH = 4.8004 > 4.7

7 0
3 years ago
Which compound is a glycol?
mixer [17]

Answer:

CH3—CH2—O—CH2—CH3 is the compound of glycol.

8 0
3 years ago
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