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3 years ago

What is the initial material of hydraulic lime?

Chemistry

1 answer:

dalvyx [7]3 years ago

3 0

Answer:

The raw material of hydraulic lime is a limestone.

Such type of limestone is called Argillaceus.

From~Charminglex~

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A gas at a constant temperature of 300. K, a pressure of 200. kPa, and a volume of 15.0L was decreased to a volume of 10.0 L. Wh

Vesnalui [34]

Answer:

300 kPa

Explanation:

P2=P1V1/V2

You can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

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3 years ago

PLEASE HELP I will mark brianliest

Stells [14]

Answer:

I feel A I am not you sure though. could also be D

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3 years ago

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SbF5 mass ratio and atomic ratio

Marina CMI [18]

Answer:

SbF5

Mass ratio = 1.28 : 1

And atomic ratio = 1 : 5

7 0

3 years ago

For which of the following reactions is Î"Hârxn equal to Î"Hâf of the product(s)?

Serga [27]

Answer:

1, 2, 3 and 4.

Explanation:

Hello,

Standard enthalpy of reaction is defined by the difference between the products whole enthalpy and the reagents whole enthalpy. It is known that an element's (by itself or as a diatomic gas) enthalpy of formation is 0, turning out into an equality between the enthalpy of formation and the products whole enthapy. Thus, the reactions that accomplish the given questions are 1, 2, 3 and 4, since the reagents are just the elements sodium, chlorine, carbon and oxygen.

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3 years ago

Boiling point of a solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water. kB= 0.512 c/m.

Nookie1986 [14]

100.133 degree celsius is the boiling point of the solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water.

Explanation:

Balanced eaquation for the reaction

CaCl2 + 2H20 ⇒ Ca(OH)2 + HCl

given:

mass of CaCl2 = 15.2 grams

mass of the solution = 57 grams

Kb (molal elevation constant) = 0.512 c/m

i = vont hoff factor is 1 as 1 mole of the substance is given as product.

Molality is calculated as:

molality = $\frac{grams of solute}{grams of solution}$

= $\frac{15.2}{57}$

= 0.26 M

Boiling point is calculated as:

ΔT = i x Kb x M

= 1 x 0.512 x 0.26

= 0.133 degrees

The boiling point of the solution will be:

100 degrees + 0.133 degrees (100 degrees is the boiling point of water)

= 100.133 degree celcius is the boiling point of mixture formed.

4 0

3 years ago