A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th
1 answer:
Answer:
The radius of the curve is 9,183.67 m.
Explanation:
Given;
velocity of the jet plane, v = 600 m/s
acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²
The radius of the curve is calculated from centripetal acceleration formula as given below;
Therefore, the radius of the curve is 9,183.67 m.
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