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Nady [450]
2 years ago
6

Which statement about moons is incorrect?

Physics
2 answers:
mestny [16]2 years ago
5 0
Moons never have an atmosphere.
Liono4ka [1.6K]2 years ago
5 0
The obvious question is B
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A dragster race car can accelerate from rest to incredible speeds. In one case a dragster is able to finish the 305 m run in 3.6
Dafna1 [17]

Answer:

45.89m/s²

Explanation:

Given

Distance S = 305m

Time t = 3.64s

To get the acceleration during this run, we will apply the equation of motion:

S = ut+1/2at²

Substitute the given parameters into the formula and calculate the value of a

305 = 0+1/2 a(3.64)²

304 = 1/2(13.2496)a

304 = 6.6248a

a = 304/6.6248

a = 45.89m/s²

Hence the average acceleration during this run is 45.89m/s²

4 0
2 years ago
A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west. what impulse is required to decrease the speed of t
zzz [600]
The impulse required to decrease the speed of the boat is equal to the variation of momentum of the boat:
J=\Delta p=m \Delta v
where
m=225 kg is the mass of the boat
\Delta v=v_f-v_i=15 m/s-21 m/s=-6 m/s is the variation of velocity of the boat
By substituting the numbers into the first equation, we find the impulse:
J=m\Delta v=(225 kg)(-6 m/s)=-1350 N s
and the negative sign means the direction of the impulse is against the direction of motion of the boat.
8 0
3 years ago
Read 2 more answers
A man inside the water seea a fish in water. will the fish appear to man in it's actual position? will the man appear to fish in
weqwewe [10]

Answer:

no

Explanation:

due to the refraction of light,meaning bending of light when it passes from diffrent mediums with diffrent densities

(probably mot the complete ans but smtg like this)

4 0
3 years ago
Read 2 more answers
An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its
Zinaida [17]

Answer:

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force = 12.0v+4.00v^2

Equating both, we have

    784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0

  So v = 12.58 m/s or v = -15.58 m/s ( not possible)

 So terminal velocity of object = 12.58 m/s    

3 0
3 years ago
Factors that affect acceleration due to gravity.<br>​
hram777 [196]

Answer

Factors Affecting Acceleration Due to Gravity

 

(1) Position on the planetary surface, it is higher at the axis (poles),

(2) Mass of the planet, higher with planets of larger masses

(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.

Mark me as Brainlist if this answer is helpful for you

8 0
3 years ago
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