3. A 900N mountain climber scales a
1 answer:
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Answer:
a) It takes 6,37 s b) The Velocity is -59,43 m/s
Explanation:
The initial variables of the balloon are:
Xo = 0 m
Vo = 3 m/s
After one minute the situation is the following:
t= 60 s
X1 = Xo + Vo*t
X1= 0 m + 3 m/s * 60s
X1= 180m
So when the bag falls, its initial variables are the following:
Xo = 180m
X1 = 0m
Vo = 3 m/s
V1= ?
a= -9,8 m/s2
The ecuation of movement for this situation is:
X = Vo*t + 1/2 a*
So:
-180m = 3m/s*t+ 1/2*-9,8 m/s2 *
To solve this we have
a=-9,8/2
b=3
c=180
The formula is:
Replacing, we get to 2 solutions, where only the positive one is valid because we are talking about time.
<u>So the answer a) is t= 6,37 s</u>
With that answer we can find the question b), with the following movement formula.
Vf = Vo + at
Vf = +3 m/s + (-) 9,8 m/s2 *6,37s
b) Vf = -59,43 m/s
<h2>The time taken is 1 second </h2>
Explanation:
Suppose the first diamond falls for t seconds
The downward displacement S₁ = u t + g t²
here u = 0 , because it was at rest initially
Thus S₁ = g t² I
Similarly second diamond moves for time ( t - 0.9 ) sec
The distance covered by it is
S₂ = g (t - 0.9 )²
The separation between the two is 13 m
Thus S₁ - S₂ = 13 m
g t² -
g t² + 0.9 g t - 0.4 g = 13
or 9 t = 13 - 4 = 9
Hence t = 1 sec