It depends on how fast you are going and in orincipal no
Impulse on the object: -20 kg m/s
Explanation:
The impulse exerted on an object is a vector quantity equal to the product between the force exerted on the object and the time interval during which the force is applied.
The impulse exerted on an object is also equal to its change in momentum. Mathematically,

where:
m is the mass of the object
u is the initial velocity
v is the final velocity
For the object in this problem, we have
m = 5 kg
u = +6 m/s
v = +2 m/s
Therefore, its impulse is:

The negative sign means the direction of the impulse is opposite to the direction of motion of the object.
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Answer:
(a) 43.2 kC
(b) 0.012V kWh
(c) 0.108V cents
Explanation:
<u>Given:</u>
- i = current flow = 3 A
- t = time interval for which the current flow =

- V = terminal voltage of the battery
- R = rate of energy = 9 cents/kWh
<u>Assume:</u>
- Q = charge transported as a result of charging
- E = energy expended
- C = cost of charging
Part (a):
We know that the charge flow rate is the electric current flow through a wire.

Hence, 43.2 kC of charge is transported as a result of charging.
Part (b):
We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

Hence, 0.012V kWh is expended in charging the battery.
Part (c):
We know that the energy cost is equal to the product of energy expended and the rate of energy.

Hence, 0.108V cents is the charging cost of the battery.
The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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