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Morgarella [4.7K]
3 years ago
15

A wave is approaching a barrier that has a small hole at the center. Which describes the change in the wave as it encounters the

barrier?
A.The wave will slow down

B.The wave will bend or defract

C.The wave will bounce in the opposite direction, or reflact.

D.The wave will increase its speed
Physics
2 answers:
AleksAgata [21]3 years ago
8 0

The answer is

B. The wave will bend or defract

Lisa [10]3 years ago
4 0

Answer: The correct answer is "The wave will bend or defract".

Explanation:

Diffraction: It is the phenomenon in which the light gets bend around the corner of the aperture or a slit. There is a spreading of the waves as they pass through an aperture.

The wavelength of the wave is comparable or greater than the size of the aperture to observe diffraction. If the wavelength of the wave is not comparable or greater than the size of the aperture then in this case, the diffraction is unnoticeable.

In the given problem, a wave is approaching a barrier that has a small hole at the center. A small hole is aperture here. The wave will bend or defract. The diffraction phenomenon will occur in this case.

Therefore, the correct option is (B).

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a stone is dropped from top of a tower of 50m high ,simltaneously another stone is thrown upward with a speed of 20m/s find the
aleksklad [387]
At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is

             H = 50 - (1/2 G Q²) ,

and the height of the stone that was tossed straight up
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             H  =  20Q - (1/2 G Q²) .

The stones meet when them's heights are equal,
so that's the time when

                         <span>50 - (1/2 G Q²)  =  20Q - (1/2 G Q²) .

This is looking like it's going to be easy.

Add  </span><span>(1/2 G Q²)  to each side.
Then it says
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Divide each side by 20:          2.5  =  Q .

And there we are.  The stones pass each other

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