Water has a specific heat of 4.186 J/g*C. How much energy would be required to raise the temperature of 10 g of water by 10 C?
1 answer:
Energy(heat) required to raise the temperature of water : 418.6 J
<h3>Further explanation </h3>Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Specific heat of water = 4.186 J/g*C.
∆T(raise the temperature) : 10° C
mass = 10 g
Heat required :
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Explanation:
Assuming that the final (equilibrium) temperature of the system is above the melting point of ice, such that all ice in the container melts in this process thus
and
Let the final temperature of the system be . Thus
(converted to kilojoules)
-
The fact that energy within this system (assuming proper insulation) conserves allows for the construction of an equation about variable .
Confirm the uniformity of units, equate the two expressions and solve for :
which goes against the initial assumption. Implying that the final temperature does <em>not</em> go above the melting point of water- i.e.,
. However, there's no way for the temperature of the system to go below
; doing so would require the removal of heat from the system which isn't possible under the given circumstance; the ice-water mixture experiences an addition of heat as the hot block of lead was added to the system.
The temperature of the system therefore remains at ; the only macroscopic change in this process is expected to be observed as a slight variation in the ratio between the mass of liquid water and that of the ice in this system.