Answer:
1 mole of CaC₂ will produce 26g of C₂H₂ or 64.1g of CaC₂ will produce 26g of C₂H₂
Explanation:
Hello,
To solve this question, we'll require a balanced chemical equation of reaction between calcium carbide and water.
Equation of reaction
CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂
Molar mass of calcium carbide (CaC₂) = 64.1g/mol
Molar mass of water (H₂O) = 18g/mol
Molar mass of calcium hydroxide (Ca(OH)₂) = 74g/mol
Molar mass of ethyne (C₂H₂) = 26g/mol
From the equation of reaction, 1 mole of CaC₂ will produce 1 mole of C₂H₂
1 mole of CaC₂ = mass / molar mass
Mass = 1 × 64.1
Mass = 64.1g
1 mole of C₂H₂ = mass / molar mass
Mass = 1 × 26
Mass = 26g
Therefore, 1 mole of CaC₂ will produce 26g of C₂H₂
Note: this is a hypothetical calculation since we were not given the initial mass of CaC₂ that starts the reaction
<h3>The <u>
complete question</u>
would be:</h3>
In a common laboratory experiment in general chemistry, students are asked to determine the relative amounts of benzoic acid and charcoal in a solid mixture. Benzoic acid is relatively soluble in hot water, but charcoal is not. Devise a method for separating the two components in the mixture.
<h3>The <u>
solution</u> for that would be:</h3>
First you put the mixture in hot water and allow the benzoic acid to separate. Next funnel it and then see what's on the funnel paper. Lastly, heat the leftover water and see what's left after it evaporates.
<h3><u>What are laboratory experiments ?</u></h3>
- Using controlled surroundings to test theories, researchers may develop laboratory experiments.
- Laboratories are rooms or specially constructed facilities within buildings that are often found on college and university campuses and are utilized for academic research.
- It's crucial to differentiate between experiments and other kinds of research investigations carried out in lab settings.
- Even if a research study takes place in a lab, it is not always an experiment.
- In order to evaluate causal conclusions regarding the links between independent and dependent variables, laboratory studies, like all genuine experimental designs, use procedures of random assignment of participants and control groups.
To view more about experiments, refer to:
brainly.com/question/17143317
#SPJ4
you would change one element to a diffrent element
Answer: 1-Exhale 2-inhale 3-contracted diaphragm 4-relaxed diaphragm.
Step by step explanation: hope this helped! Have a great day.
