<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
((12+5)+20÷4))+4
first is parentheses inside out
12+5 = 17
((17)+20÷4))+4
now divide inside the parenthesis
(17+5)+4
next parentheses
22+4
26
Answer: 26
Hey there! Hello!
The easiest way to solve this problem is by subtracting one value from the other. In order to find how much weight Emily gained in two months, we need to find the difference between her initial weight and how much she weighed at the end of two months:

You can see that I added a zero onto the end of the 8.2. This just evens out the amount of numbers and makes the problem easier to visualize while keeping the amount the same.
From the result of the problem, Emily gained 1.95 pounds in two months.
I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
Answer:
64
Step-by-step explanation: