Answer:
0.0432 M H2SO4
Explanation:
First, we want to find the moles of MNaOH used. We know that Molarity x Liters = moles. 0.160M x 0.0210L = 0.00336 moles MNaOH
to find the moles of H2SO4, we can use a mol ratio.
0.00336mol MNaOH x (1Mol H2SO4 /2mol MNaOH)
= 0. 00168 mol H2SO4
I found the mol ratio by looking at the coefficients in front of the molecules I knew(MNaOH) and the molecule I needed to find(H2SO4)
then, to find Molarity, we do mol/Liters
0.00168 mol/ 0.0388L =. 0.0432 M H2SO4
You can convert mL to L by dividing by 1000
the significant figures of this problem is 3, so my final answer will also have 3 sig figs.
Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
The London dispersion force (intermolecular force) <span>is a temporary attractive </span>force between molecules.
There is a bout 7 grams of protein in 1 ounce of meat, so 7*70=
Below are the steps to get the answers:
<span>1.) write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
2.) You are given everything needed to calculate
q=heat transfer=2.2*10^2, H3PO4 moles= 1.5*10^-3, NaOH moles=5.0*10^-3
3.) equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first
4.) Now plug in variables
DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj, </span>
