Answer:
See figure 1
Explanation:
In this question, we have to start with the <u>protonation of the double bond</u>. In carvone we have two double bonds, so, we have to decide first which one would be protonated.
The problem states that the <u>terminal alkene</u> is the one that would is protonated. Therefore, we have to do the <u>protonation</u> in the double bond at the bottom to produce the <u>carbocation number 1</u>. Then, a hydride shift takes place to produce the <u>carbocation number 2</u>. A continuation, an <u>elimination reaction</u> takes place to produce the <u>conjugated diene</u>. Then the diene is protonated at the <u>carbonyl group</u> and with an elimination reaction of an hydrogen in the <u>alpha carbon</u> we can obtain <u>carvacol. </u>
Answer:
c is the answer
step by step explanation is not
To form the value of 1500 in
scientific notation, it is
<span><span>
1.
</span>By simply
moving the period which separates the whole numbers from the decimal numbers
between 1 and 5. </span>
<span><span>
2.
</span>Thus, it
then becomes 1.5 </span>
<span><span>
3.
</span>Next, is
you have to count how many moves the period made from its point of origin
hence, for this value is 3</span>
<span><span>4.
</span>Therefore,
the scientific notation for the number is 1.5 x 10^3</span>
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11
CsxOy
x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2
y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2
Cs₂O₂ cesium peroxide
The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J
