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AnnZ [28]
3 years ago
10

In the picture above, what is the period of the pendulum? (Remember to include a unit)

Physics
1 answer:
-BARSIC- [3]3 years ago
6 0
69 i agree with her hope this helps
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Discuss in detail, one way in which atomic nuclear decay takes place. What is the significance of atomic nuclear decay? Analyze
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Atomic Nuclear's significance is that it proves the idea of quantum tunneling in the branch of quantum physics. The barriers that keep nuclear energy together are very high. Quantum mechanics sometimes tells us that particles can sometimes tunnel through the walls over they cannot climb and it happens at random intervals and unpredictably. 
<span>The social implications of using this process are the same as the social implications of using any natural phenomenon.</span>
5 0
4 years ago
Find the magnitude of the electric field at a point midway between two charges +13.6 x 10-9 C and +61.0 x 109 C separated by a d
Ostrovityanka [42]

Answer:

Ep =  3797.05  N/C  in the direction leaving the charge q₂ towards point P

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

Data

k=  8.99*10⁹ N*m²/C²

q₁ = +13.6 x 10⁻⁹C

q₂ = +61.0*10⁻⁹C

d₁ =d₂= 33.5 cm = 0.335 m

Look at the attached graphic:

E₁: Electric Field at point  P due to charge q₁. As the charge  q₁ is positive   (q₁+) ,the field leaves the charge

E₂: Electric Field at point  P due to charge q₂. As the charge q₂ is positive (q₂+) ,the field leaves the charge

E₁ = k*q₁/d₁² = 8.99*10⁹ *13.6 *10⁻⁹/(0.335)² = 1089.45 N/C

E₂ = k*q₂/d₂²=- 8.99*10⁹ *61*10⁻⁹/(0.335)² = - 4886.5   N/C

Magnitude of the electric field at a point midway between q₁ and q₂

Ep= - 4886.5+ 1089.45 = -3797.05  N/C

Ep =  3797.5  N/C  in the direction leaving the charge q₂ towards point P

6 0
3 years ago
The radius of Mars is 3397 km; and its mass is 6.42x10²³ kg. What is the acceleration due to gravity at an altitude of 485 km ab
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Answer:nfeergnjknrtgrth

Explanation:

4 0
3 years ago
Read 2 more answers
An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou
frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is u=3\ m/s

speed of camera u_1=20\ m/s

Initial separation between camera and balloon is d_o=5\ m

Suppose after t sec of  throw camera reach balloon then,

distance travel by balloon is

s=ut

s=3\times t

and distance travel by camera to reach balloon is

s_1=ut+\frac{1}{2}at^2

s_1=20\times t-\frac{1}{2}gt^2

Now

\Rightarrow s_1=5+s

\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t

\Rightarrow 5t^2-17t+5=0

\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}

\Rightarrow t=\dfrac{17\pm 13.747}{10}

\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is  t=0.3253\ s

velocity is given by

v=u+at

v=20-10\times 0.3253

v=16.747\ m/s

and position of camera is same as of balloon so

Position is =5+3\times 0.3253

=5.975\approx 6\ m

8 0
3 years ago
What us a magnetic domain?​
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7 0
3 years ago
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