<u><em>Answer:</em></u>
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<u><em>9.2 N, with significant figure rounding (2 s.f.)
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<u><em>Explanation:</em></u>
<u><em>This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:</em></u>
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<u><em>Note that where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.</em></u>
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<u><em>Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg. </em></u>
<u><em>m = 0.15 kg</em></u>
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<u><em>The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.</em></u>
<u><em>v₀ = 4.4 m/s [down]</em></u>
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<u><em>When it comes to a stop, the egg will have a velocity of 0.</em></u>
<u><em>v = 0 m/s</em></u>
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<u><em>The time it takes for the egg to stop is 0.072 seconds.</em></u>
<u><em>Δt = 0.072 s</em></u>
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<u><em>Therefore, if down is positive, then</em></u>
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<u><em> </em></u>
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<u><em>We round to two significant figures since every quantity has two sig. figs.</em></u>
<u><em>We only care about the magnitude, not direction. The answer is 9.2 N.</em></u>
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<u><em>5.0</em></u>
