The acceleration of the ball is 1.27 X 10⁵ m/s²
The Newtons second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
Given,
Mass = 145 kg
Force = 18,400 N
We need to calculate the acceleration
Using formula of acceleration(a)
a = F/m where F= force and m= mass
Put the values in the formula,
a = 18,400/(145 X 10⁻³) = 1.27 X 10⁵ m/s²
Therefor, the acceleration of the ball is 1.27 X 10⁵ m/s².
Learn more about the Newton's second law with the help of the given link:
brainly.com/question/27573481
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In physics, there are already derived equation that are based on Newton's Law of Motions. The rectilinear motions at constant acceleration have the following equations:
x = v₁t + 1/2 at²
a = (v₂-v₁)/t
where
x is the distance travelled
v₁ is the initial velocity
v₂ is the final velocity
a is the acceleration
t is the time
Now, we solve first the second equation. Since it mentions that the car comes eventually to a stop, v₂ = 0. Then,
-5 = (0-v₁)/t
-5t = -v₁
v₁ = 5t
We use this new equation to substitute to the first one:
x = v₁t + 1/2 at²
15 = 5t(t) + 1/2(-5)t²
15 = 5t² - 5/2 t²
15 = 5/2 t²
5t² = 30
t² = 30/5 = 6
t = √6 = 2.45
Therefore, the time it took to travel 15 m at a deceleration of -5 m/s² is 2.45 seconds.
I think it's 3. within an outer arm
Answer:
A 1.56 see below
Explanation:
I will assume the 45 degree force is upward
vertical component = 600 sin 45 = 424.26 N
added to the other vertical force will total 824.26 N
F = ma
824.26 = 100 * a shows a = 8.24 m/s upward
Now we have to assume the mass is ALSO acted on by gravity and this value is given as 9.8 ( so downward is positive)
9.81 - 8.24 = 1.56 m/s^2
