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wariber [46]
3 years ago
15

A bowl has 2 gold marbles, 3 blue marbles and 5 white marbles. A marble is randomly selected and then placed back in the bowl. Y

ou do this 5 times. What is the probability of choosing 1 gold marble, 1 blue marble and 3 white marbles?
Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

2/10 or 1/5 gold, 3/10 blue and 5/10 or 2/5 white

Step-by-step explanation:

2+3+5=10

since you do this 5 times and get 5 marbles it can be:

2/10 or 1/5 gold, 3/10 blue and 5/10 or 2/5 white

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If you solve using the equation for the constant of proportionality, y/x = k with k = 4/5 and y = 2/3, what is the value of x?
ruslelena [56]

Answer:

x=5/6

Step-by-step explanation:

k=4/5

3 and 5 can go into 15

10/15 and 12/15

10/15 divided by x =12/15

x=5/6

6 0
3 years ago
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A new company started with 12 founding members. It is quadrupling its membership base every year. Write an equation to model thi
Nutka1998 [239]
It could be 12x4=48


It should be idk if I’m right
4 0
3 years ago
7.5% of what number is equal to 85% of 200?
Ksivusya [100]
Solving:

\frac{7.5}{100} *x =  \frac{85}{100} * 200

\frac{7.5x}{\diagup\!\!\!\!\!\!\!\!100} = \frac{17000}{\diagup\!\!\!\!\!\!\!\!100}
7.5x = 17000
x =  \frac{17000}{7.5}
x = 2266.6666... \:\to \boxed{\boxed{x \approx 2266.67}}\end{array}}\qquad\quad\checkmark
8 0
3 years ago
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Ten less than 3 times a number is the same as the number plus 4. What is the number?
lys-0071 [83]

Answer:

3x-10=x+4

Step-by-step explanation:

6 0
3 years ago
Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

b) The probability is 0.08547

Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

Var-X_{2} =3.076(1-(16/52))=2.13

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0
3 years ago
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