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3 years ago

A 47-inch piece of steel is cut into three pieces so that the second piece is twice as

Mathematics

1 answer:

Aneli [31]3 years ago

4 0

Answer:

<h2> first piece: 5 in</h2><h2> second piece: 10 in</h2><h2> third piece: 32 in </h2>

Step-by-step explanation:

x - the length of the <u>first piec</u>e

2x - twice the length of the first piece (the length of the <u>second piece</u>)

6x - six times the length of the first piece

two inches more:

6x+2 - the length of the <u>third piec</u>e

first + second + third = 47 in {total length of the pieces of steel}

x + 2x + 6x + 2 = 47

9x + 2 = 47

9x = 45

x = 45:9

x = 5 in

first piece: 5 in

second piece: 2×5 = 10 in

third piece: 6×5 + 2 = 30 + 2 = 32 in

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Answer:

see explanation

Step-by-step explanation:

y = 1 is the equation of a horizontal line parallel to the x- axis.

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Answer:

y = -1/2x + 3

Step-by-step explanation:

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b = 3

Slope is simply rise over run, so for a simple line graph like this, we can count how many points the line goes up, or down, and right, or left, to reach the next point. According to the given graph, the slope is -2/4 or -1/2.

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3 years ago

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Answer:

The equation that matches the function shown is option;

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Step-by-step explanation:

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3 years ago

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ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

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5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

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Step-by-step explanation:

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