By the law of universal gravitation, the gravitational force <em>F</em> between the satellite (mass <em>m</em>) and planet (mass <em>M</em>) is
<em>F</em> = <em>G</em> <em>M</em> <em>m</em> / <em>R </em>²
where
<em>• G</em> = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant
• <em>R</em> = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet
Solve for <em>M</em> :
<em>M</em> = <em>F R</em> ² / (<em>G</em> <em>m</em>)
<em>M</em> = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (<em>G</em> (6 × 10³ kg))
<em>M</em> ≈ 2.8 × 10¹⁴ kg
In series circuit, Req = R₁ + R₂ + R₃ + ···
In parallel circuit, ![\frac{1}{Req} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} +...](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BReq%7D%20%20%3D%20%5Cfrac%7B1%7D%7BR1%7D%20%2B%20%5Cfrac%7B1%7D%7BR2%7D%20%2B%20%5Cfrac%7B1%7D%7BR3%7D%20%2B...)
<h3>Q7.</h3>
total resistance in the upper branch = R₂ + R₃ = R₂ + 2
![\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BReq%7D%20%3D%20%5Cfrac%7B1%7D%7BR2%2BR3%7D%20%2B%20%5Cfrac%7B1%7D%7BR1%7D)
![\frac{1}{4} = \frac{1}{R2+2} +\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7BR2%2B2%7D%20%2B%5Cfrac%7B1%7D%7B6%7D)
R₂ + 2 = 12
R₂ = 10Ω
<h3>Q8.</h3>
![\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BReq%7D%20%3D%20%5Cfrac%7B1%7D%7BR2%2BR3%7D%20%2B%20%5Cfrac%7B1%7D%7BR1%7D)
![\frac{1}{Req} = \frac{1}{2+1} + \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BReq%7D%20%3D%20%5Cfrac%7B1%7D%7B2%2B1%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D)
Req = 1.7Ω
Answer:
The density of the woman is 950.8 kg/m³
Explanation:
Given;
fraction of the woman's volume above the surface = 4.92%
then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%
the specific gravity of the woman ![= \frac{95.08}{100 } = 0.9508](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B95.08%7D%7B100%20%7D%20%3D%200.9508)
The density of the woman is calculate as;
![Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water](https://tex.z-dn.net/?f=Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%3D%20%5Cfrac%7BDensity%20%5C%20of%20%5C%20the%20%5C%20woman%20%7D%7BDensity%20%5C%20of%20%5C%20fresh%20%5C%20water%20%7D%5C%5C%5C%5C%20Density%20%5C%20of%20%5C%20the%20%5C%20woman%20%20%3D%20Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%5C%20%5Ctimes%20%5C%20Density%20%5C%20of%20%5C%20fresh%20%5C%20water)
Density of fresh water = 1000 kg/m³
Density of the woman = 0.9508 x 1000 kg/m³
Density of the woman = 950.8 kg/m³
Therefore, the density of the woman is 950.8 kg/m³
Answer:
she's wrong because she is and there it doesn't say she's right