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liraira [26]
3 years ago
15

Calculate the average time it took the car to travel 0. 25 and 0. 50 meters with three washers attached to the pulley. Record th

e averages, rounded to two decimal places, in Table C of your Student Guide. What is the average time it took the car to travel 0. 25 meters? seconds What is the average time it took the car to travel 0. 50 meters? seconds.
Physics
1 answer:
EastWind [94]3 years ago
6 0

The Speed of a moving vehicle can be measured. The average time it will taken too cover both distance are shown below;

The average travel times traveled are :

0.25 meters = 2.23 seconds

0.50 meters = 3.13 seconds

Therefore, the Average travel time to cover 0.25 meters is:

(Trial 1 + Trial 2 + Trial 3) ÷ 3

(2.24 + 2.21 + 2.23) / 3 = 6.68 = 2.2266 = 2.23 seconds ( approximated to 2 decimal places).

Therefore, the Average travel time to cover 0.50 meters is

(Trial 1 + Trial 2 + Trial 3) ÷ 3

(3.16 + 3.08 + 3.15) / 3 = 9.39 ÷ 3 = 3.13 seconds

Conclusively, the average time taken to cover 0.25 and 0.50 meters is said to be 2.23 and 3.13 seconds for the both..

Learn more from

brainly.com/question/25738530

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MA_775_DIABLO [31]
<span>Answer: The acceleration of 10 kg object is greater than that of 18 kg object.

Explanation:
According to Newton's Second law:
F = ma --- (A)

Let's find the acceleration for both 10 kg and 18 kg objects!
The net force on both of these masses = F = 20N

(1) Acceleration of 10 kg object
Mass = m = 10 kg
Plug in the values in equation (A):
20 = 10 * a
Acceleration = a = 2 m/s^2

(2) Acceleration of 18 kg object
Mass = m = 18 kg
Plug in the values in equation (A):

20 = 18 * a
Acceleration = a = 1.11 m/s^2


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4 years ago
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A 375-pound concrete cylinder has a base area of 144 square inches. with the cylinder resting on its base, the pressure exerted
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The pressure exerted by the concrete cylinder is 2.60 pound/in².

We need to know about the pressure to solve this problem. Pressure is a unit that describes how much force is applied to a surface area. It can be determined as

P = F / A

where P is pressure, F is force and A is area.

From the question above, we know that

F = 375 pound

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By substituting the given parameters, we can calculate the pressure

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Thus, the pressure should be 2.60 pound/in².

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6 0
1 year ago
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
Andreas93 [3]

Answer:

A. when the mass has a speed of zero

Explanation:

In mass-spring system, the velocity and the acceleration are in anti-phase, which means that when one of the two quantities is maximum, the other one is zero, and vice-versa.

In fact:

- When the displacement of the spring is zero (x=0), the velocity is maximum, due to conservation of energy. In fact, as the displacement is zero, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is zero, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be maximum, and so the velocity (v) is also maximum. On the cotnrary, acceleration (a) is directly proportional to the restoring force of the spring, given by

F=-kx

so we see that when x=0, then the force is zero: F=0, and so the acceleration is zero as well.

- When the displacement of the spring is maximum, the velocity is zero, due to conservation of energy. In fact, as the displacement is maximum, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is maximum, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be zero, and so the velocity (v) is also zero. On the cotnrary, since acceleration (a) is directly proportional to the restoring force of the spring, given by

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Based on this, the correct answer is

A. when the mass has a speed of zero


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The correct answer is D. Amount of time and area of physical contact between the substances.

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