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3 years ago

An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?

Physics

2 answers:

Karo-lina-s [1.5K]3 years ago

7 0

Answer: 2km/m/s/s

Explanation:

10km divided by 5m/s/s = 2km/m/s/s

Lynna [10]3 years ago

6 0

Answer:

hope helps

Explanation:

In a weightless environment a force of 5 Newtons is applied horizontally to the right on a rock with a mass of 1 kg and to a pebble with a mass of 0.1 kg.

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In Bolt’s fastest 100 meter, he accelerated from the starting block to a speed of 27.8 mi/hr in 9.58 s. What was his acceleratio

Gemiola [76]

Answer: 2.90mi/hr/s

Explanation:

Acceleration = Final Velocity - Initial over time

Acceleration = 27.8mi/hr over 9.58s.

Answer is 2.90mi/hr/s

Hope I Helped!

8 0

2 years ago

Name the characteristics of electro magnetic waves that i) increases ii) remains constant in the electromagneticspectrum as one

Paul [167]

As we move from Radiowaves to UV waves in electromagnetic spectrum we know that the wavelength is maximum for radio waves while its frequency is minimum

PART (i)

So as we move from radiowaves to UV region

the Frequency will increase

Part (ii)

As we move from Radiowaves to UV region all the parts must have same speed in same medium

All parts will move with speed of light

so Speed will remain the same

4 0

4 years ago

A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.

Luda [366]

Answer:

The value is $x = 200000000 \ m$

Explanation:

From the question we are told that

The distance between the earth and the moon is $d = 200000 \ km$

Generally ,

$1 \ km = 1000 \ m$

$200000 \ km \to x \ m$

=> $x = \frac{200000 * 1000}{1 }$

=> $x = 200000000 \ m$

4 0

3 years ago

What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.

elena-14-01-66 [18.8K]

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

3 0

3 years ago

Read 2 more answers

What is the speed of a wave on a string with a wavelength of 1.75 m and a frequency of 2.0 Hz

deff fn [24]

Answer:

V=3.5 m/s

Explanation:

V=(F)(W)

V=(2)(1.75)

V= 3.5 m/s

7 0

3 years ago