An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?
2 answers:
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Answer:
Acceleration:
Explanation:
The acceleration of an object is equal to the rate of change of velocity:
where
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
For the space probe in this problem, we have:
u = 100 ft/s (initial velocity)
v = 5000 ft/s (final velocity)
t = 0.5 s (time taken)
Therefore, the acceleration is
Complete Question
Captain Hook is fighting Peter Pan, and they are about to step onto a tightrope strung horizontally between two masts that are 16 m apart. When Pan and Hook are standing exactly halfway between the masts, the rope makes a 3 anglewith the horizontal. The rope has a diameter of 0.02 m and a Youngs modulus of 35 GPa.
What is the combined mass,in kilograms, of Peter Pan and Captain Hook?
Answer:
Their combined mass is
Explanation:
A sketch that describes the question is shown on the first uploaded image
From the question we are told that
The distance apart is
The angle the rope makes is
The diameter of the rope is
The Young modulus is
From the diagram we see that the elongation of the rope can be mathematically evaluated as
And applying SOHCATOH rule
Substituting values
And
The Tension on the rope can be mathematically represented as
Where A is the area and is mathematically represented as
Substituting values
Now Substituting values into the formula for the tension on the rope
From the diagram we can mathematically evaluate the the weight of peter and hook as
Where
Now substituting this into the equation and making m the subject
Substituting values
Note SOHCATOH is
