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kvasek [131]
3 years ago
10

This is an example of a ____________ resource using _______.

Physics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

A

Explanation:

I guess but not sure cause wind is soemthing you can get back electricity is soemthing you can't

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A crane lifts a load of 15000N to a height 40m in 50 seconds. Calculate the power of the crane​
Nataly [62]

Answer:

P = 12000 W

Explanation:

General data:

  • F = 15000 N
  • d = 40 m
  • t = 50 s
  • P = ?

Work is force times unit of distance. So in order to calculate the power we must first calculate the work.

Formula:

  • \boxed{\bold{W=\frac{F}{d}}}

Replace and solve

  • \boxed{\bold{W=\frac{15000\ N}{40\ m}}}
  • \boxed{\bold{W=600000\ J}}

once the work is found, we proceed to find the power according to the formula:

  • \boxed{\bold{P=\frac{W}{t}}}
  • \boxed{\bold{P=\frac{600000\ J}{50\ s}}}
  • \boxed{\boxed{\bold{P=12000\ W}}}

The power of the crane is <u>12000 Watts.</u>

Greetings.

6 0
3 years ago
If there was a small sphere freely suspended in plane poiseuille flow, how would you go about using linearity to prove that the
Blizzard [7]

Answer Explanation :

Poiseuille equation: this equation is used for non ideal flow this is used for the calculation of pressure in laminar flow it is physical law we know that fluid in laminar flow, flows across the pipe whose diameter is larger than the length of pipe

in mathematical form the equation can be expressed as

Q = \frac{(P_2-P_1) r^{4}\times \pi}{8\times\eta \times l }

where η is the cofficient of viscosity

now if we assume a small sphere of radius a is suspended freely in the plane of the laminar flow then for assuring that the sphere does not migrate with the flow we have to calculate the rate of flow of the liquid

8 0
3 years ago
Need help! Photo says all! Will mark brainliest :)
AVprozaik [17]

Answer:

C-D

Explanation:

As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.

Divide 6 meters by 3 seconds to find the speed:

6 ÷ 3 = 2 m/s

B-C is not moving due to a straight line as said in the graph, so speed is

0 m/s.

There is also C-D since the car traveled from a distance of 9 meters

(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)

Divide 9 meters by 3 seconds to get the speed:

9 ÷ 3 = 3 m/s

Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.

A-D does not count here as the line has no connection between point A and point D.

Cheers!

6 0
3 years ago
A 2,200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.40 m before coming into contact
love history [14]

Answer:

The magnitude of Force is 8.58×10⁵N and direction is upwards

Explanation:

The work beam does on the pile driver is given by

W=(FCos180°)Δx= -F(0.088m)

From work energy theorem

W_{nc}=(KE_{f}-KE_{i})+(PE_{f}-PE_{i})\\W_{nc}=1/2m(vf^{2}-vi^{2})+mg(yf-yi)

Choosing y=0 at the the level where the driver first contacts the beam and vi=0 at yi=+3.40m and comes to rest again vf=0 at yf= -0.088m

So

-F(0.088m)=1/2m(0-0)+2,200kg(9.81m/s^{2} )(-0.088m-3.40m)\\-F(0.088)=-75508.224\\F=75508.224/0.088\\F=8.58*10^{5} N

The magnitude of Force is 8.58×10⁵N and direction is upwards

6 0
3 years ago
A block oscillating on a spring has period T = 2.8 s . (Note: You do not know values for either m or k. Do not assume any partic
olasank [31]

Answer:

Part a)

T = 3.96 s

Part b)

T = 1.98 s

Part c)

T = 2.8 s

Explanation:

As we know that time period of spring block system is given as

T = 2\pi\sqrt{\frac{m}{k}}

T = 2.8 s

Part a)

If the mass of the block attached is doubled

then we will have

T' = 2\pi\sqrt{\frac{2m}{k}}

T' = \sqrt2 T

T' = 3.96 s

Part b)

If the spring constant is doubled

then we have

T' = 2\pi\sqrt{\frac{m}{2k}}

T' = \frac{T}{\sqrt2}

T' = 1.98 s

Part c)

If the amplitude is halved but mass and spring constant will remain the same

so here we know that time period does not depends on Amplitude

so we will have

T = 2\pi\sqrt{\frac{m}{k}}

T = 2.8 s

7 0
3 years ago
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