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kvasek [131]
3 years ago
10

This is an example of a ____________ resource using _______.

Physics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

A

Explanation:

I guess but not sure cause wind is soemthing you can get back electricity is soemthing you can't

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A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
2 years ago
A publication which contains news on current events​
german

Answer:

A newspaper is a serial publication which contains news on current events of special or general interest.

3 0
2 years ago
Read 2 more answers
a 150 kg object takes a 1.5 minute travel to a 2500 straight path it begins you trip at traveling 120 miles an hour and it decel
crimeas [40]
I believe it’s acceleration is -1.11 m/s^2
5 0
3 years ago
Find the electric field a distance z above a circular ring carrying a constant line charge. For extra credit you may derive the
lora16 [44]

Answer:

F = 8.23 × 10⁻⁸N

Explanation:

F= kq²/r²

k= 9×10⁹Nm²/C²

q= 1.6×10⁻¹⁹C

r= 5.29×10⁻¹¹m

F= 9×10⁹× (1.6×10⁻¹⁹)²/  (5.29×10⁻¹¹)²

F = 8.23 × 10⁻⁸N

4 0
3 years ago
Which of the following best describes gravitational force?
miss Akunina [59]

Answer:

An attraction between two objects that have mass :)

7 0
2 years ago
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