If there was a small sphere freely suspended in plane poiseuille flow, how would you go about using linearity to prove that the
1 answer:
Answer Explanation :
Poiseuille equation: this equation is used for non ideal flow this is used for the calculation of pressure in laminar flow it is physical law we know that fluid in laminar flow, flows across the pipe whose diameter is larger than the length of pipe
in mathematical form the equation can be expressed as
Q =
where η is the cofficient of viscosity
now if we assume a small sphere of radius a is suspended freely in the plane of the laminar flow then for assuring that the sphere does not migrate with the flow we have to calculate the rate of flow of the liquid
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Answer:
r = 0.22m
Explanation:
To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.
Then, you have:
(1)
m: mass of the particle = 20g = 20*10-3 kg
ac: centripetal acceleration = ?
q: charge of the particle = 5*10^-6C
Fe: electric force between the charges
The electric force is given by:
(2)
r: radius of the orbit
q': charge of the particle at the center of the orbit = -5*10^-6C
Furthermore, the centripetal acceleration is:
(3)
v: speed of the particle = 7m/s
You replace the expressions (2) and (3) in the equation (1) and solve for r:
Finally, you replace the values of all parameters in the previous expression:
The radius of the circular trajectory is 0.22m
Answer:
Acceleration is -30000 mi/h²
Distance travelled in the 3 seconds of deceleration is 261.888 feet
Explanation:
t = Time taken for the car to slow down = 3 s =
u = Initial velocity = 75 mi/h
v = Final velocity = 50 mi/h
s = Displacement
a = Acceleration
Equation of motion
Acceleration is -30000 mi/h²
Converting to feet
1 mile = 5280 feet
0.0496 mile = 0.0496×5280 = 261.888 feet
Distance travelled in the 3 seconds of deceleration is 261.888 feet