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The moment of the resultant of these two forces with respect to O 376 lb-ft CCW which is <span>about moment center point O.</span>
Answer:
205N
Explanation:
The net force (F) is the difference between the applied force(
) and the kinetic frictional force(
). i.e
F =
-
-----------------(i)
Note that;
= μmg
Where;
μ = coefficient of kinetic friction
m = mass of the body
g = acceleration due to gravity = 10m/s²
Equation (i) then becomes;
F =
- μmg -------------------(ii)
<em>Given from question;</em>
m = mass of motorcycle = 150kg
μ = 0.03
= 250N
Substitute these values into equation (ii) as follows;
F = 250 - (0.03 x 150 x 10)
F = 250 - (45)
F = 205N
Therefore, the net force applied to the motorcycle is 205N
there are 28 neutrons present
Answer:
<em>585lb</em>
Explanation:
Given the formula for calculating the magnitude of the resultant force as;

<em>Given </em>
<em></em>
<em></em>
<em>Hence the magnitude of the resultant force is 585lb</em>
I calculated on a sheet and used differentiation to solve the problems.