3 years ago

Cardiovascular exercise can

Physics

2 answers:

sesenic [268]3 years ago

6 0

Increase your resting heart rate

UkoKoshka [18]3 years ago

3 0

Can <span>get your heart rate up and increases blood circulation throughout the body.</span>

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A cheetah runs at a speed of 27.6 m/s. If the

aleksklad [387]

Answer:

256.68m

Explanation:

that is the procedure above

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3 years ago

An astronaut drops a rock on the surface of an asteroid.The rock is released from rest at a height of 0.86 m above the ground, a

SCORPION-xisa [38]

Answer:

$a_y=0.92m/s^2$

Explanation:

To solve this problem we use the formula for accelerated motion:

$y=y_0+v_{y0}t+\frac{a_yt^2}{2}$

We will take the initial position as our reference ( $y_0=0m$ ) and the downward direction as positive. Since the rock departs from rest we have:

$y=\frac{a_yt^2}{2}$

Which means our acceleration would be:

$a_y=\frac{2y}{t^2}$

Using our values:

$a_y=\frac{2(0.86m)}{(1.37s)^2}=0.92m/s^2$

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3 years ago

What is the phase of the moon when the moon is positioned between the sun and earth?

vladimir2022 [97]

Answer:

Solar eclipse

Explanation:

A solar eclipse is when the moon passes between the sun and Earth, causing it to go dark and to give the moon a halo effect :D hope this helped!

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2 years ago

A vertical spring stretches 9.6 cm when a 1.3 kg block is hung from its end. (a) Calculate the spring constant. This block is th

tatiyna

Answer:

F = - K x

a) K = 1.3 kg * 9.8 m/s^2 / .096 m = 133 kg/sec^2

b) ω = (K/m)^1/2 angular frequency of SHM

ω = (133 / 1.3)^1/2 = 10.1 / sec

f = 2 π ω = 6.28 * 10.1 / sec = 63.5 / sec

P = 1/f = .0157 sec

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3 years ago

What amount of energy is needed for an electron to jump from n = 1 to n = 4?

liberstina [14]

Answer:

$E=2.04\times 10^{-18}\ J$

Explanation:

We need to find the energy for an electron to jump from n = 1 to n = 4.

The energy in transition from 1 state to another is given by :

$E=\dfrac{-2.18\times 10^{-18}}{n^2}\ J$

The difference in energy for n = 1 to n = 4 is:

$E=-2.18\times 10^{-18}\times (\dfrac{1}{4^2}-1)\\\\E=2.04\times 10^{-18}\ J$

So, the required energy is equal to $2.04\times 10^{-18}\ J$ .

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3 years ago