All categories

3 years ago

Which of the following is a result of the transfer of energy?

2 answers:

7 0

OPTION C) MAGNETISM IS THE RIGHT ANSWER....

Explanation:

MAGNETISM IS TRANSFER THE ENERGYS. BECAUSE IN THE CHOOSE IT OTHER OPTION ARE NOT HAVE ANY ENERGY. SO MAGNETISM IS THE RIGHT ANSWER....

HOPE IT HELP.....✌✌✌

Lostsunrise [7]3 years ago

3 0

Answer: Sound

Explanation: it's asking which of the following is a result of transfer of energy and sound comes from vibrations

You might be interested in

Una persona A tiene cierta cantidad de masa y una persona B tiene la mitad de masa de la persona A ¿como es el peso de B respect

musickatia [10]

Answer:

El peso de la persona B es la mitad del peso de la persona A.

Explanation:

El peso de la persona B puede calcularse con la siguiente ecuación:

$P_{B} = m_{B}g$ (1)

En donde:

$m_{B}$ : es la masa de la persona B

g: es la gravedad

Dado que la persona B tiene la mitad de la masa de la persona A, tenemos:

$m_{B} = \frac{m_{A}}{2}$ (2)

En donde:

$m_{A}$ : es la masa de la persona A

Al introducir la ecuación (2) en (1) nos queda:

$P_{B} = \frac{m_{A}}{2}g$ (3)

Sabemos que el peso de la persona A está dado por:

$P_{A} = m_{A}g$ (4)

Entonces, al introducir la ecuación (4) en (3) tenemos:

$P_{B} = \frac{P_{A}}{2}$

Por lo tanto, el peso de la persona B es la mitad del peso de la persona A.

Espero que te sea de utilidad!

5 0

3 years ago

The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t

jek_recluse [69]

Answer:

$e=3367.2J$

% $e=1.43$ %

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

$v_{r}=10km/h=2.77m/s$

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

$v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s$

Knowing that we can calculate Kinetic energy for the real and experimental speed

$E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J$

$E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J$

Now, the potential error in her calculated kinetic energy is:

$e=E_{r}-E_{e}=(234023-230656)J=3367.2J$

% $e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43$ %

4 0

4 years ago

A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.

fgiga [73]

The vertical velocity of the projectile upon returning to its original is 17. 74 m/s

<h3>How to determine the vertical velocity</h3>

Using the formula:

Vertical velocity component , Vy = V * sin(α)

Where

V = initial velocity = 36. 6 m/s

α = angle of projectile = 29°

Substitute into the formula

Vy = 36. 6 * sin ( 29°)

Vy = 36. 6 * 0. 4848

Vy = 17. 74 m/s

Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s

Learn more about vertical velocity here:

brainly.com/question/24949996

#SPJ1

8 0

2 years ago

A student charges a balloon and then brings it near a metal sphere hanging from the

Hunter-Best [27]

Answer:

Explanation:

the balloon has a negative charge and the metal sphere has a positive charge

3 0

3 years ago

Read 2 more answers

While traveling on a horizontal road at speed vi, a driver sees a large rabbit ahead and slams on the brakes. The wheels lock an

MA_775_DIABLO [31]

Answer:

μk = (Vf - Vc)/(T×g)

Explanation:

Given

Vi = initial velocity of the car

Vf = final velocity of the car

T = Time of application of brakes

g = acceleration due to gravity (known constant)

Let the mass of the car be Mc

Assuming only kinetic frictional force acts on the car as the driver applies the brakes,

The n from Newtown's second law of motion.

Fk = Mc×a

Fk = μk×Mc×g

a = (Vf - Vc)/T

Equating both preceding equation.

μk×Mc×g = Mc × (Vf - Vc)/T

Mc cancels out.

μk = (Vf - Vc)/(T×g)

4 0

4 years ago

Which of the following is a result of the transfer of energy￼?

Which of the following is a result of the transfer of energy?