If the empirical formula of a compound is CH2, which of the following could be a possible molecular formula for this

What will happen if you add a mild acid to a solution that is buffered at ph = 7?

allsm [11]

The pH of the solution will be lowered. Currently the solution is Neutral (salt water). Adding an acid will turn the solution slightly acidic

6 0

4 years ago

What is the windward side of the sand dune

earnstyle [38]

Answer:

A dunes windward side is the side where the wind is blowing and pushing material up. A dunes slip face is simply the side without wind. A slipface is usually smoother than a dunes windward side. A collection of dunes is called a dune belt or dune field.

Explanation:

Hope this helps...

7 0

3 years ago

What happens to Earth when it is farthest from the sun?

Nata [24]

Answer:

Explanation:

The Earth is closest to the Sun, or at the perihelion, about 2 weeks after the December Solstice, when it is winter in the Northern Hemisphere. Conversely, the Earth is farthest away from the Sun, at the aphelion point, 2 weeks after the June Solstice, when the Northern Hemisphere is enjoying warm summer months.

Therefore, most countries might have two or four seasons.

hope this helps.

5 0

3 years ago

Read the given equation. 2Na + 2H2O ? 2NaOH + H2 During a laboratory experiment, a certain quantity of sodium metal reacted with

emmasim [6.3K]

Answer:

The number of moles of Na metal that used initially = 0.70 mol.

The quantity of Na metal used initially to produce 7.80 of H₂ gas = 16.02 g.

Explanation:

It is a stichiometry problem.

2Na + 2H₂O → 2NaOH + H₂,

The balanced equation shows that 2.0 moles of Na metal react with 2.0 moles of water to produce 2.0 moles of NaOH and 1.0 mole of H₂,

Firstly, we need to convert the volume of H₂ (7.80 L) produced to no. of moles (n) using the ideal gas law: PV = nRT,

where, P is the pressure of the gas in atm (P at STP = 1.0 atm),

V is the volume of the gas in L (V = 7.80 L),

n is the number of moles in mole,

R is the general gas constant (R = 0.082 L.atm/mol),

T is the temperature of the gas in K (T at STP = 0.0 °C + 273 = 273.0 K).

∴ The number of moles of H₂ gas (n) = PV / RT = [(1.0 atm)(7.80 L)] / [(0.082 L.atm/mol.K)(273.0 K)] = 0.35 mol.

Using cross multiplication:

2.0 moles of Na will produce → 1.0 mole of H₂, from the stichiometrey.

??? moles of Na will produce → 0.35 mole of H₂.

∴ The number of moles of Na metal that used initially = (2.0 mol)(0.35 mol) / (1.0 mol) = 0.70 mol.

Now, we can get the quantity of Na metal using the relation:

∴ mass = n x molar mass = (0.70 mol)(22.989 g/mol) = 16.02 g.

6 0

3 years ago

What is the volume of water needed to prepare 5000 ml of 0.1 M HCL from a stock solution of4 M

Karo-lina-s [1.5K]

Hey There :

Volume initial = ?

Volume final = 5000 mL

Molarity initial = 4 M

Molarity final = 0.1 M

Therefore :

Mi * Vi = Mf * Vf

4 * vi = 0.1 * 5000

4 vi = 500

Vi = 500 / 4

Vi = 125 mL

Answer A

Hope this helps!

5 0

3 years ago